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Answer

Let he borrowed P for 5% and 2500-P fro 7%

then P x 2 x 5/100 + (2500-P) x 2 x 7/100 = 265

or 10P  + 14(2500-P) = 26500

or 4P = 8500

so P = 2125

so he borrowed Rs 2125 at 5% and Rs(2500-2125) = Rs 375 at 7% interest

Answer

5x+7y=26500

x+y=2500  X 5

5x +5y=12500

2y=4000

y=2000

x=500

Answer
Let the amount z borrowed @7%. So 2500-z borrowed @5%. I = (z×7×2)/100+(2500-z)×5×2/100 =265. To simplify calculation let us break 7 as 5+2 the equation becomes 4z/100+ 2500×10/100= 265 or 4z/100= 265 - 250 or 4z=1500. So z = 375. He borrowed Rs375 @7% and Rs2125@5%.
Answer
Rs. 2125 @ 5%, Rs. 375 @ 7%
Answer
Let the amount z borrowed @7% so 2500-z borrowed @5%. I = (z×7×2)/100+(2500-z)×5×2/100 =265. To simplify calculation let us break 7 as 5+2 the equation becomes 4z/100+ 2500×10/100= 265 or 4z/100= 265 - 250 or 4z=1500. So z = 375. He borrowed Rs375 @7% and Rs2125@5%
Answer
Ans- Rs. 2125 @ 5%, Rs. 375 @ 7%
Answer
x*2*5/100 +(2500- x)*2*7/100 =265 x=2125 5%.....2125 7%......375
Answer
P=2500, Time(T)=2 suppose, first money lender give X at interest of 7% p.a. So, second give money (2500-X) at interest of 5% p.a. S.I = P*R*T/100 So total SI= [P1*R1*T1/100]+[P2*R2*T2/100]=265 265 = [X*7*2/100]+[(2500-X)*5*2/100] 265*100=[14X]+[(2500-X)10] 26500 =4X+25000 26500-25000= 4X 1500= 4X X= 375 2500-X= 2125 So he borrowed 2125 at the interest of 5% and 375 at the interest of 7%

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