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Answer

in 1hr the reduces 108km distance between them.

108km in 1hr

1km in 1/108

0.45km in 1/108*0.45=1/240 hr

3600/240=15sec

Answer
Total dist= 450 m speed 108* 5/18= 30 m/sec so, t = 15 sec
Answer
v1=36km/hr,v2=72km/hr, L1=200m, L2= 250m t=(200+250)/(36000+72000)/3600=15sec
Answer
total dist= 450 m speed 108* 5/18= 30 m/sec so, t = 15 sec
Answer
if Total length= 200+250=450m and S1 = 36km/h or if we convert it 10m/s then S2 = 72km/h or 20 m/s then Relative Speed = S1+S2 = 30m/s now Total Time= Total Length/Total Speed 450/30 = 15 seconds
Answer
Here is your answer. This question is based on relative velocity. When two objects or vehicles travels towards each other the resultant velocity is the sum of the individual velocities. If they are travelling away from each other the resultant velocity is the difference of the two velocities. In this question, First convert the unit of speed from km/hr to metre/sec as the length is in metres. For converting to m/sec multiply by 5/18. 36 km/hr=36*5/18=10 m/sec 72km/hr=72*5/18=20 m/sec The resultant velocity is 20+10=30 m/sec The length you should take as 200+250=450 m since both should completely pass each other from engine to last boggie. Time =distance/speed=450/30= 15 seconds.
Answer
36km/hr=36*5/18=10m/s 72 " " = 20m/s Time =200+250/10+20=15sec
Answer
T= D/S = (200+250)/(10+20) = 450/30 s = 15 s
Answer
Total length= 200+250=450m S1 = 36km/h or 10m/s S2 = 72km/h or 20 m/s Relative Speed = S1+S2 = 30m/s Total Time= Total Length/Total Speed 450/30 = 15 seconds.
Answer
Total lengh=200+250=450m s1=36km/h s2=72km/h if they are running towards each other relative speed=s1+s2=108km/h( 108x(5/18))=30m/s then time at which they cross each other T=(450)/30=15seconds. incase they are running in same direction relative speed will be s2-s1 and rest same speed distance formula

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