Answers and Solutions

Answer

/ans. a) x>y

Let, the intiial population be p. 

After increase by x%, it becomes P*(100+x)/100.

Then after decrease by y%, it becomes P*(100-y).(100+x)/10000.

ATP, P*(100-y).(100+x)/10000 = P.

=> 10000 + 100x - 100y - xy = 10000  .   => 100(x-y) = xy  .   => x - y = xy/100 .

Now, xy is obviously > 0, since x and y both are positive numbers.

So, x-y > 0 .   => x>y

Answer

Answer:

Let the initial population of the country  =  P

Percentage increase in the population in the year 2019 = x

Therfore absolute increase in population = Px/100 ..........................A

Total population in the year 2019 = P+(Px/100) =  P1(say)

Therfore P1 > P  

Now percentage reduction in population in the year 2020 due to Covid = y

Absolute decrease in population = P1y/100      .....................B  

But incease in population in the tear 2019 =  decrease in population in the year 2020

So equating  "A " & "B"  we get

Px/100  =   P1Y/100  or     x = (P1/P)*y

But  P1>P .  Therfore   x >y 

Hence Correct Option :  a

Answer

Answer:

Let the initial population of the country  =  P

Percentage increase in the population in the year 2019 = x

Therfore absolute increase in population = Px/100 ..........................A

Total population in the year 2019 = P+(Px/100) =  P1(say)

Therfore P1 > P  

Now percentage reduction in population in the year 2020 due to Covid = y

Absolute decrease in population = P1y/100      .....................B  

But incease in population in the tear 2019 =  decrease in population in the year 2020

So equating  "A " & "B"  we get

Px/100  =   P1Y/100  or     x = (P1/P)*y

But  P1>P .  Therfore   x >y 

Hence Correct Option :  a

Answer

Answer:

Let the initial population of the country  =  P

Percentage increase in the population in the year 2019 = x

Therfore absolute increase in population = Px/100 ..........................A

Total population in the year 2019 = P+(Px/100) =  P1(say)

Therfore P1 > P  

Now percentage reduction in population in the year 2020 due to Covid = y

Absolute decrease in population = P1y/100      .....................B  

But incease in population in the tear 2019 =  decrease in population in the year 2020

So equating  "A " & "B"  we get

Px/100  =   P1Y/100  or     x = (P1/P)*y

But  P1>P .  Therfore   x >y 

Hence Correct Option :  a

Answer

Let Initial(starting) pollution = p

pollution increased in 2019 is x% = px/100

let q =total pollution in 2019  = p+(px/100)

pollution decreased by y% in 2020 = qy/100 (decrease)

therefore, pollution in 2020 = q - (qy/100) = p+(px/100) - (1/100)(py+(pxy/100))

given starting pollution  = pollution in 2020

=> p = p+(px/100) - (1/100)(py+(pxy/100))

=> px/100 = (1/100)(py+(pxy/100))

=> px = py+(pxy/100)

=> x = y + (xy/100)

=> x>y

option a