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The expression  (A+B)³ = A³ + 3A²B + 3AB² + B³, a plain algebraic identity, is possible for 2 square matrices if and only if AB = BA, i.e., the multiplication should be commutative in this case.  

AB = [1  1 \ 1  0][a  b \ c  d] = [a+c    b+d \ a   b]

 

and

 

BA = [a  b \ c  d][1  1\ 1  0] = [a+b  a \ c+d  c]

 

Thus, b = c and a = b + d

 

|(b+c)/(a-d)| = |2b/(b+d-d)| = 2

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