   ### Vinit K Male, 26 Years

Associated for 2 Years 6 Months
Class 11 - 12 Tutor

#### Activity Score - 295

• I teach at My Home
• I go to Student's Home
Area: Sector 63
Location: Noida, India
Qualification :
• B.Tech/B.E. (National Institute of Technology - 2016)
• Total Experience:
3 Years
• Hourly Fees:
INR 200
Tutoring Experience :
I believe that breaking any complex concepts to smaller chunks to the extent that you can start playing around with the info till you enjoy exploring it is what makes the journey easy at the same time thought provoking.
Tutoring Option :
Home Tuition Only
Tutoring Approach :
I make teaching experience interesting by conducting discussions and quizes as to have a better understanding that how much the student has imbibed and what more we need to work on. I work according to a planned schedule so the syllabus is completed on time and we have ample time of revision. This makes student work under no pressure.
Teaches:
 Class 9 - 10 Physics History Chemistry Social Studies CBSE INR 200 / Hour Class 11 - 12 History Political Science CBSE Board INR 200 / Hour Class 6 - 8 Mathematics Physics Chemistry Social Studies CBSE INR 200 / Hour
• ## Question: A train passes an electric pole in 10 seconds and a 130 m long platform in 20 se...

Posted in: Bank PO | Date: 04/09/2017

Speed = Distance/Time Let us assume the length of the train be L1 and as it doesn't mention about the speed, so the speed is same for crossing the pole or the 130m long platform. As it crosses the pole it moves the distance of its length. So, Speed(S) =L1/10 Now again when it crosses the platform it will travel (L1+130). So, Speed(S) =(L1+130)/20 Solve these two equations and we'll get the L1's value as 130m.

• ## Question: A house was sold at 10% discount for Rs. 45000. At what price would the house ha...

Posted in: Mathematics | Date: 04/09/2017

See the problem u may be encountering is its language. The question is saying that the house is sold for Rs 45000. It means is sold @45000 after giving the discount.

so, let's assume X be the price at which, if sold at no discount. And if we subtract 10% of X from X then we'll get the amount at which it is sold which is Rs45000.

X-10%of X= 45000

X(1-10/100)= 45000

X=45000*100/90

• ## Question: Ajay can do a piece of work in 4 hours, Bijay and Chaman together can do it in 3...

Posted in: Bank PO | Date: 04/09/2017

Ajay=A

Bijay=B

Chaman=C

A takes 4days for a piece of work i.e. 96 hours. So the amount of work done in 1hour will be 1/96 work.

96 hour----------1 work

1hour-------1/96 work

Now, if A & C work together and complete it in 2hr.

2hour= 1/96 +1/Y   --------(lets Y be the time taken by C) Equation-1

Solving this equation we'll get Y=96/191 ----------Equation-2

Now, 3hour = 1/Y + 1/X ---------(lets X be the time taken by B)-----equation-3

Putting the value of Y from equation 2 in equation 3, we'll get the value of X as 97/96hour.

X=97/96 hours

X=97/96*60 minutes

X=60.625 minutes.

• ## Question: Bhola can do a certain work in 20 days while Saheb can do the same work in 30 da...

Posted in: Mathematics | Date: 04/09/2017

B does the work in 2o days. So, the amount of work he'll do in 1day is:

20days----------------------1 work

1day-------------------------1/20 work

similarly, S does in 1 day-------------------1/30 work

Ratio of their work= Wb/Ws =(1/20)/(1/30)

Wb/Ws=3/2--------------------------------Eq-1

now if they work together then the time taken by them is: 1/T = 1/20 +1/30

T=30*20/(30+20)

T= 12days

For 12 days they get Rs.3840. So,

for 1 day they'll get = 3840/12= Rs. 320

now, their work ratio is 3:2 so, they'll get their payment in their work ratio.

Rb= 320*3/(3+2) = 320*3/5= 192 for 1 day. So, B will get for 12 days= 192*12 = Rs. 2304

Rs= 320*2/(3+2) = 320*2/5=128 for 1 day. So, S will get for 12days =128*12= 1536

check: 1536+2304= 3840.

• ## Question: Prasun travelled some distance with a speed of 50 kmph. With what speed should ...

Posted in: Bank PO | Date: 04/09/2017

Let the distance travelled by Prasun be D with a speed of 50kmph.

Speed= distance/time

50=D/T1 => T1=D/50   equation-1----------(let T1 be the time taken)

When he returns, he travels at S2 and  So, S2 =D/T2 => T2=D/S2  equation-2--

Average Speed = total distance travelled/ total time taken

60kmph=(D+D)/(T1+T2)

putting from eq-1 and eq-2, and by solving

60=2D/(D/50+D/S2)

60= 2*50*S2/(50+S2)

60*(50+S2)=100S2

S2=300/4= 75

So, we'll get S2=75kmph

• ## Question: Two pipes B and F can fill the tank in 10 hours and 15 hours, respectively. If b...

Posted in: Bank PO | Date: 04/09/2017

pipe B fills in 10hrs so, in 1hr it will fill 1/10 portion of the tank.

i.e. 10 hours------1 tank

1 hour -------1/10 tank

similarly pipe F,

1 hour--------1/15 tank

And now M is the outlet pipe which is releasing the water. We can say this pipe is adding negative water.

So, the time was taken together :

1/30 = 1/10+ 1/15 -1/M ---------------(suppose M be the time taken by pipe M to empty the full tank)

solving this,  M= 7.5 hours. So, the pipe M will take 7.5hrs to empty the tank.