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MPT 179755
  • Male, 45 Years
  • Activity Score89

Sanjay

Associated for 3 Years 6 Months
Mentor
  • Qualification:
    B.Com.(Hons.)
  • Experience:
    I have more than 4 years of experience. I have experience in Computer Technologies as well. I teach Mathematics, Computer, All Subjects and Mental Mathematics of the CBSE Board for the standard I - V. I also teach Comput... More [+]
  • Teaches:
    Mathematics, Computer, All Subjects, School level computer, Hindi, Computer Science, Statistics, IT & Computer Subjects, Economics, Accountancy, Software Testing, MCA Subjects, Data Science, BCA Subjects, Mental Maths, DBMS & RDBMS, Oracle Training, PL/SQL
  • Board:
    CBSE Board, CBSE, ICSE, Local State Board
  • Areas:
  • Pincode:
    201301
Profile Details
Profile Details

Qualification :

B.Com.(Hons.)

Total Experience :

4 Years

I have more than 4 years of experience. I have experience in Computer Technologies as well. I teach Mathematics, Computer, All Subjects and Mental Mathematics of the CBSE Board for the standard I - V. I also teach Computer Science, Hindi, School Level Computer and all other subjects of the CBSE Board for the standard VI - VIII.

Tutoring Option:

Home Tuition Only

Tutoring Approach:

Every student is unique therefore the technique is different for every student. The teachings are modified to suit the individual needs.  I am friendly and supportive person who gets excellent result by offering general education advice and find that my pupils normally make speedy progress towards their goals.

Hourly Fees [INR]:

250.00

Class 1 - 5 Mathematics, Computer, All Subjects, CBSE Board INR 150.00 /hour
Class 11 - 12 Accountancy, Economics, Statistics, IT & Computer Subjects, CBSE, ICSE, Local State Board INR 350.00 /hour
Technology BCA Subjects, MCA Subjects, Software Testing, Data Science INR 500.00 /hour
Academic Enrichment Mental Mathematics INR 300.00 /hour
Class 6 - 8 Computer Science, Hindi, School level computer, All Subjects, CBSE INR 250.00 /hour
Data Science / DBMS DBMS & RDBMS, Oracle Training, PL/SQL INR 400.00 /hour
Answer
Answer
  • Answer:

    The four PowerPoint views are: 

    Slide View-  The Slide view shows a single slide. In Slide view, you work on one slide at at time.  In Slide view, you have access to all the tools on the Tool Palette as well as buttons on the Toolbar. 

    Outline View-  The Outline view shows all the titles and body text in your presentation.  In Outline view, you can move slides around within your presentation and also edit your text. 

    Slide Sorter View-  The Slide Sorter view shows you a miniature of each slide in your presentation.  You can drag slides around on the screen to reposition them in this view.  You can also select and copy multiple slides should you want to use them in other presentations. 

    Notes View-  The Notes view lets you create speaker's notes.  Each page corresponds to a slide in your presentation and includes a reduce image of the slide.  You can draw and type in Notes view the way you can in Slide View. 

  • Question: What do you mean by the SLIP?

    Posted in: Computer | Date: 16/01/2016

    Answer:

    SLIP - Serial Line Internet Protocol. It is to communicate between two machines.

  • Question: What are the advantages of PL/SQL?

    Posted in: Computer | Date: 16/01/2016

    Answer:

    There are following advanges:

    1. Integration of procedural constructs with SQL 2. Modularized program development 3. Improved performance 4. Integration with Oracle tools 5. Portability 6. Exception handling

  • Question: What are the UNIQUE constraints?

    Posted in: Computer | Date: 16/01/2016

    Answer:

    A unique constraint is a single field or combination of fields that uniquely defines a record. Some of the fields can contain null values as long as the combination of values is unique. Each and every value should appear only once in the list. 

  • Question: What is data conversion function?

    Posted in: Computer | Date: 16/01/2016

    Answer:

    Type of functions which helps to convert one type of data to another, i.e., string to char. There are following data conversion functions:

    to_char, to_number, to_date etc.

  • Question: What is the use of the RESTORE command in BASIC ?

    Posted in: Computer | Date: 20/01/2016

    Answer:

    To allow DATA statements to be reread from a specified line.

  • Question: What is the difference between web page and home page?

    Posted in: Computer | Date: 20/01/2016

    Answer:

    The home page is the first page that a visitor discovers when he wants to visit asite. There is only one home page.

    All the pages are web pages.

  • Question: What is WWW?

    Posted in: Computer | Date: 20/01/2016

    Answer:

    World Wide Web. All the resources available over the net is called WWW.

  • Question: What are the UNIQUE constraints?

    Posted in: Computer | Date: 15/08/2017

    Answer:

    A unique constraint is a single field or combination of fields that uniquely defines a record. Some of the fields can contain null values as long as the combination of values is unique. In Oracle, a unique constraint can not contain more than 32 columns. A unique constraint can be defined in either a CREATE TABLE statement or an ALTER TABLE statement.

  • Question: What is data conversion function?

    Posted in: Computer | Date: 15/08/2017

    Answer:

    Oracle inbuilt function library contains type conversion functions. There may be scenarios where the query expects input in a specific data type, but it receives it in a different data type. In such cases, Oracle implicitly tries to convert the unexpected value to a compatible data type which can be substituted in place and application continuity is not compromised. Type conversion can be either implicitly done by Oracle or explicitly done by the programmer. Implicit data type conversion works based on a matrix which showcases the Oracle's support for internal type casting. Besides these rules, Oracle offers type conversion functions which can be used in the queries for explicit conversion and formatting. As a matter of fact, it is recommended to perform explicit conversion instead of relying on software intelligence. Though implicit conversion works well, but to eliminate the skew chances where bad inputs could be difficult to typecast internally.

  • Question: List and explain various debugging techniques.

    Posted in: Computer | Date: 15/08/2017

    Answer:

    These six techniques can go a long way in assisting the debugging process: 1. Simplify complex data: Substitute complex analog inputs with digital, synthetic, known, and repeatable data. If a counting pattern does the trick to start, use a counting pattern. For algorithms with coefficients (such as filters), replace the production coefficients with a simpler set of coefficients (such as all zeros except one full-scale coefficient). 2. Divide and conquer: Home in on the location of the problem as much as possible before trying to understand it. This can save significant time both in simulation and in the lab on hardware in the long run. To elaborate, let's say you've got a chained set of processing-intensive signal processing algorithms; let's call them A, B, C, D. When you stimulate A and observe D, you notice a problem. If you can narrow down that the input to C looks fine, but the output of C is bad, you've just homed in on the bug and the problem is likely within C. Now you can strip away dealing with the additional complexities of A, B, and D. This concept also works from a bottom-up perspective. Verify that the lower level functions work first, then work up through the layers of abstraction. For example, perhaps you've got an analog data logger algorithm. Start by verifying the low level A/D interface, physical memory interface, and physical communication bus interface. Then move up a layer to verify functions like data handlers and routers. Finally, verify the top level of the data logger. 3. Slow the process down: Slow down clocks and data rates. Perhaps some timing requirement isn't being met. Maybe one algorithm isn't synchronized with another. Perhaps one of the algorithms that needs to be data-driven was accidentally coded to be clock-driven. Or maybe one device is trying to push data too quickly to another. 4. Only change one variable at a time: When there are multiple inputs, it can be valuable to isolate them and only change one input at a time, observing the system response. The trick here is to identify all the inputs that induce a change in the output of the system. This is related to fault isolation and activation. 5. Create off-line models: These models should match as closely as possible the real-time algorithm, for bit-level comparison. This is most useful for non-intuitive transformations (such as matrix operations) where it's too challenging to understand what the output should look like relative to the input. If the real-time algorithm is fixed-point and the off-line algorithm is floating-point, there may be small discrepancies that accumulate and cause problems. 6. Start from a known-good state: Slowly tune the input until something breaks, and the bug is observable. This can be helpful for scenarios where overflow may be occurring. For example, if bit wrapping is suspected, slowly increase the amplitude at the input until the problem is observed. Similarly, if there are buffers in use, start by feeding a small amount of data into the algorithm and slowly increasing until the suspected condition occurs. Alternatively, maybe a control loop that breaks with large transients may appear fine with smaller deviations around a steady-state condition.

  • Answer:

    The average speed is 8 miles per hour.

    The total time taken to complete tw course  are 20 +25 = 45 minutes.

    ! course  = 3 miles. So 2 course = 2 X 3 = 6 miles.

    45 minutes taken to complete miles  = 6 miles

    1 minute = 6 / 45

    60 minutes = (6 * 60) / 45 = 8 miles

     

     

  • Answer:

    Let the CP of 1 Kg is 100.

    So the SP after profit will be 100 + 14% of 100 = 100 +14 = 114

    Now, he is selling 90% of the actual quantity. So, 114/90 * 100 = 126.67

    Actual profit = 126.67 - 100 = 26.67% 

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