• Male, 54 Years
• Activity Score547

## Prabhat R

Stay Focused Stay Sharp
• I teach at My Home
• I go to Student's Home
• Online
• Qualification:
M.Sc
• Experience:
I impart tuition in Maths, Science and School-level Computer based on MINIMUM STUDIES, MAXIMUM SCORING. All my students are quite satisfied with my way of teaching. Its absolutely my responsibility to deal with their performance ... More [+]
• Teaches:
School level computer, Physics, Mathematics, Computer Science, Chemistry, Bengali, IT & Computer Subjects, Business Mathematics, Polytechnic Entrance, JECA Exam, IIT JEE Mains, CET, BCA Entrance, CS - Foundation, PSAT, MBA Entrance, LSAT, IBSAT
• Board:
CBSE/ICSE, All Boards
• Areas:
• Pincode:
700031
Profile Details

#### Qualification :

 M.Sc University of Calcutta 1979

#### Total Experience :

25 Years

I impart tuition in Maths, Science and School-level Computer based on MINIMUM STUDIES, MAXIMUM SCORING. All my students are quite satisfied with my way of teaching. Its absolutely my responsibility to deal with their performance and make them excel in academics. I am teaching for last 27+ years in private/group tuition.

Tuitions offered for classes and subjects are as under:

VII - X  : Physics, Chemistry, Maths and Computer and IT;

XI - XII : Maths and Computer and IT

Thank you.

#### Tutoring Option:

I Can Manage Both

#### Tutoring Approach:

My Tuition is based on 'MINIMUM STUDIES, MAXIMUM SCORING' for which I ensure understanding of the CORE KNOWLEDGE, again for which if I require to teach the subject at a much lower level than his/her present level, I ensure doing that also.

500.00

#### Tuition Schedule:

• Sunday : --
• Monday : --
• Tuesday : --
• Wednesday : --
• Thursday : --
• Friday : --
• Saturday : --
 Class 9 - 10 Mathematics, Physics, Chemistry, Computer Science, School level computer, Bengali, CBSE/ICSE, English Medium INR 500.00 /hour Class 11 - 12 Mathematics, Business Mathematics, Computer Science, IT & Computer Subjects, All Boards, English/Regional Language INR 500.00 /hour Engineering Entrance & IITJEE Mathematics, IIT JEE Mains, CET, JECA Exam, BCA Entrance, Polytechnic Entrance INR 500.00 /hour Test Preparation MBA Entrance, IBSAT, LSAT, PSAT INR 600.00 /hour CA CPT CS - Foundation INR 600.00 /hour Class 6 - 8 Mathematics, Physics, Chemistry, Computer Science, School level computer, Bengali, CBSE/ICSE INR 500.00 /hour
Services Offered

Yes

USD10.00

#### Online Tutoring Experience :

I am giving online tuition only for 6 year and 9 months although my experience as Home tutor and centre tutor is 20+ years.

#### Online Tools Details :

I do use white boards and other teaching aids and yahoo board along with Skype and Yahoo messenger.

#### Online Availability :

Monday to Friday: 00:00 to 03:30 and 16:30 to 20:30. Saturdays: 11:00 to 20:30. Sundays: : 00:00 to 07:00 and 08:30 to 20:30. - (All timings are in GMT)

• ## Question: A shopkeeper marks his goods 40% above the cost price and allows is customer a d...

Posted in: Mathematics | Date: 27/11/2018

Question is not clearly framed; however, if we presume Rs. 325 to be the gain amount, then the solution is as under:

Let the Cost Price(CP) be Rs. 100;

Therefore, Marked Price(MP) = Rs. 100 + 40% of Rs. 100 = Rs. 100 + Rs. 40 = Rs. 140;

Therefore, Selling Price(SP) = MP – 10% Discount on MP = Rs. 140 – 10% of Rs. 140 = Rs. 140 – Rs. 14 = Rs. 126; Therefore, his Gain = SP – CP = Rs. 126 – Rs. 100 = Rs. 26; => Gain %-age =(Gain/CP) x 100 = (26/100) x 100 = 26%(of CP);

Now, Gain Amount, i.e., 26% of CP = Rs. 325 => CP = Rs. 325/26% = Rs. 325/(26/100) = Rs. 325 x (100/26) = Rs. 32500/26 = Rs. 1250. – Ans.

• ## Question: Factorise :15pq+15+9q+25p

Posted in: Mathematics | Date: 27/11/2018

15pq + 15 + 9q + 25p =(15pq + 25p) + (9q + 15) = 5p(3q + 5) + 3(3q + 5) = (3q + 5)(5p + 3). - Ans.

• ## Question: (-15)+(-6)+3.. find the sum to 30terms

Posted in: Mathematics | Date: 06/12/2018

It is a case of an A.P. with 1st term a = -15, (2nd term = - 6),

common difference d = 2nd term - 1st term = (- 6) - (-15) = -6 + 15 = 9

and number of terms n = 30.

Therefore, Sum of 1st 30 terms of the series = n/2{2a +(n-1)d} = 30/2{2 x (-15) +(30-1)9} = 15{-30 + 29 x 9} = 15{-30 + 261} = 15 x 231 = 3465(Ans.)

Reviews
• As a teacher, Prabhat sir is excellent. His explanation power is too good. He teaches very well. His advice was very useful for me to build a successful career.
Reviewed by: Payal
• Extensive study of every topic with personal attention made every session a wonderful experience.
Reviewed by: Vaibhav Ghosh

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