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When boric acid is heated it converts to metabolic acid which on further heating gives boron trioxide.

H3BO3 ---->HBO2(-H2O)--->B2O3

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Treating alcohols with strong acids (HX) results in the formation of alkyl halides with the replacement of OH group.                   

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Primary amines can form hydrogen bonds as well as Vander Waals dispersion forces and dipole dipole interaction. Hydrogen bonds can be formed between the lone pair on the very electronegative nitrogen atom and the slightly positive hydrogen atom in another molecule.In tertiary amines all hydrogen atoms are replaced by alkyl groups,that is why formation of hydrogen bond is ruled out.This is the reason for low boiling point of tertiary amines.

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Both a and c because gem dihalides are compounds having two halogen atoms attached to the same carbon atom.

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Please post the chemical reaction.

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Both a and d are correct choices .As both have sp3 hybridisation .

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Please post relevant chemical reaction.

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D is the correct choice with bromobenzene (156 C),1-bromobutane(102 C),1 bromopropane(71 C),1- bromoethane(38 C).

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Zinc sulphide dissolves in dil HCl forming zinc chloride ,which forms  a white precipitate of zinc hydroxide when reacts with NaOH.                          

ZnCl2+ 2NaOH + Zn(OH)2-----> Zn(OH)2 + 2NaCl.                  

Zinc chloride reacts with potassium ferrocyanide forming a bluish white precipitate of zinc ferrocyanide.         

2ZnCl2+K4[Fe(CN)6].  ------> ZN2[Fe(CN)6]. +4KCl      

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Can you specify more detail?