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350.00
Class 9 - 10 | Mathematics, Physics, Chemistry, Algebra, ICSE | INR 150.00 /hour |
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C
C is the correct answre as the larger the sphere the greater the charge assuming that both have same voltage when they were connected the voltage will continue to pass between them until it becomes equal on both sphere.
V1=V2
(1/4pi *epsilon 0)*(Q1/R1) =(1/4pi *epsilon 0)*(Q2/R2)
(Q1/R1)=(Q2/R2)
Q1=(R1*Q2)/R2
since R2>R1 then the charge on the larger sphere will be more
The correct answer is B
According to newtons law the simple pendulum oscillation is based on its length not by its mass hence the oscillation would be contant
Answer B is correct
The solution to this question is based on trignometry angle theta calculations, As it is given in the question the Length of the Adjecant side is 778.5m and opposite side that is total hight of the cliff is 450m, then the angle of the flight should be calculated as tan theta because the sides in consideration are Opposite and Adjacent hence it is Tan angle , the sides values are given then degrees of the angle can be calculated by tan Inverse.that is
Opp/Adj ---> 450 / 778.5 = 0.5780346 substituting this value in tan Table the angle is 30.029 almost 30 degrees.
The passwords entering options are provided by the user is case sensitive as this feature is based on the W3c consortium guide lines , the main reason behind this is to give the user full control on password creation option yo make it somewaht difficult and safer
Note: Password are not only case sensitive but also provides special charecters selsction feature too.
The solution to this problem is given in details
1.The radius of bigger semicircle is 20 cm , beacause the small semi circle are half of the bigger semi circle as shown in the figure then:
2. The small semi circle radius is 10 cm, there are total of 3 shaded small semi circles
3 Area (shaded portion) of single semi circle is (Pi * r * r) / 2 --> ( 3.14159 * 10 * 10) / 2 = 157.0796 cm ^2
4 Shaded portion of 3 small semi circle is 157.0796 * 3 = 471.2388 cm ^2
5 Shaded portion of big semi circle - unshaded portion of small semi circle
6 Area of big semi circle (3.1459 *20 *20) / 2 =628.318 - 157.0796 = 471.2389.
Total shaded area is 471.2389 + 471.2389 = 942.477 cm ^2
Perimeter
Small semi circle perimeter is (2 * Pi * r) / 2 --->( 2 * 3.14159 * 10) / 2 = 31.4159 cm
for three semi circle is 3 * 31.4159 = 94.2477 cm
Big semi circle shaded portion perimeter is (2 * Pi * r) ---> (2 * 3.14159 * 20) = 125.6637 cm
Total shaded area perimeter is big semi crcle perimeter + three small semicircles--> 125.6637 + 94.2477= 219.9117 cm
The correct answer as per present international acceptance is seems to be A "parallax"but by close examing the major part in this method is afterall trgnometry
The correct answer is D as the magnetic quantity has both magnitude and direction of thr flux
A dimensionless quantity may have dimensionless unit Hence the answer to this question is D
The correct option is D