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Initial length[20%=1/5]=5 Final length[5+1=6] initial breadth[10%=1/10]=10 Final breadth=[10-1=9] initial area=10*5=50 Final area=9*6=54 Change in area=4 % change=4/50*100=8%
Let he travels L km for each time duration. T1=L/3, T2=L/4, T3=L/5 Now total time= 47min=47/60 hours 47/60= L( 1/3+1/4+1/5) L=1 km
(4m+6w)*8=(3m+7w)*10 On solving 1m=11w So from first equation 44w+6w=8 days 50w in 8 days So 10 w in 8*5=40 days..
South to northwest..135 degree in clockwise West to northeast 135 degree clockwise
10c+16w=56100
5c+8w=28050
15c+24w=84150 (cp)
sp=84150*1.2=100980
x1+...+x60=55*60= 3300
x1+....+x6=52*6=312
x7+......+x60=3300-312=2988
y1+.......+y6=42*6=252
new average=2988+252= 3240/60=54
grand daughter..
since beena is daughter of amar and amar is son of mayank
DW sinvce it is the only pair which is the opposite pair
9.11*10^-31kg = 1 electron
1 kg=1/(9.11*10^-31)=10.97*10^29
basically u can try previous year solved papers of bsc publication.
no only u can be able to join nationalised indian banks.
carnivorous animals have canines...which donot found in herbivorous..
n(AUB)= n(A) +n(B) -n(A intersection B)
20=12+n(B)-4
n(B)=12
Q WORKED FOR 5*12 hrs
R worked for 7*18 hrs
Q work=(5*12)/(25*12)=1/5 work
R work=(7*18)/(50*12)
hence ratio=20:21
unripe=15%, ripe=85%
total fruits =5692000
apple= 5692000*15%*45%=384210
When pressure increases, density also increases..
Anything which takes shape of the container in which it is kept..eg milk
No heat is not an example of matter
Salt water is basic in nature
121.... As it is square of 11
For daily basis give an hour for maths practice..simultaneously make a routine and prepare previous year papers atleast 2 hours per day for decided subject..
478..each number is increasing by a multiple of 7..hence the missing number would be 429+ 7*7
Prime number starting from 2.. 2;3;5;7;11;13;17;19;23;29
Male, 25 Years
1 Year
BCOM, Pursuing 3rd L...
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