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  • Female, 37 Years
  • Activity Score125

Shreshtha S

Associated for 1 Year 7 Months
  • I teach at My Home
  • Online
  • Qualification:
    M.Sc, B.Sc
  • Experience:
    M.SC (Computer Science) Banasthali Vidaypeeth, Rajasthan in year 2003 with 66.8% marks.  May 2008 - May 2010 Worked as JRF (Computer Science) at CEPTAM, DRDO, Delhi.  August 2005-June 2006 Worked as Comput... More [+]
  • Teaches:
    School level computer, Computer Science, Mathematics, Algebra, IT, BCA Tuition, Polytechnic, PL/SQL, DBMS & RDBMS, Data Structures, Computer for official job, MS Office, Basic Computer, EVS, IT & Computer Subjects, C, C++
  • Board:
    CBSE, CBSE Board, Kurukshetra University, Kurukshetra
  • Areas:
  • Pincode:
    110092
Profile Details
Profile Details

Qualification :

M.Sc Banasthali Vidyapeeth,Rajasthan 2003
B.Sc Kurukshetra University 2001

Total Experience :

2 Years

M.SC (Computer Science) Banasthali Vidaypeeth, Rajasthan in year 2003 with 66.8% marks.  May 2008 - May 2010 Worked as JRF (Computer Science) at CEPTAM, DRDO, Delhi.  August 2005-June 2006 Worked as Computer Science faculty at Chinmaya College of Science, Haridwar.  Taught Graduate (B.sc-Computer Sciences) and post Graduate (M.Sc)  May 2005-July 2005 Worked as faculty at SMT, Haridwar taught DOEACC ‘O’ level and C++

Tutoring Option:

Home Tuition Only

Hourly Fees [INR]:

500.00

Class 9 - 10 Mathematics, Computer Science, School level computer, Algebra, CBSE INR 300.00 /hour
Class 11 - 12 Computer Science, EVS, IT & Computer Subjects, Algebra, CBSE Board INR 400.00 /hour
College Level Computer Science, IT, BCA Tuition, Polytechnic, Kurukshetra University, Kurukshetra INR 500.00 /hour
Programming Language C, C++ INR 500.00 /hour
Basic Computer / Office Basic Computer, Computer for official job, School level computer, MS Office INR 300.00 /hour
Data Science / DBMS DBMS & RDBMS, PL/SQL, Data Structures INR 500.00 /hour
Answer
Answer
  • Answer:

    GIVEN: X/Y=9/16

    X+15/Y+15=2/3

    WHEN X/Y=9/16 THEN X=9Y/16...................(1)

    NOW X+15/Y+15=2/3 ...........................(2)

    ON SOLVING EQ(1) BY CROSS-MULTIPLICATION EQ. BECOMES

    3X+45=2Y+30

    45-30=2Y-3X

    15=2Y-3X

    PUT VALUE OF X AS FROM EQ(1)

    15=2Y-3(9Y/16)

    15=(32Y-27Y)/16

    15*16=5Y

    Y=3*16

    Y=48

     

    PUT THE VALUE OF Y IN EQ(1)

    X=(9*48)/16

    X=27

     

    YOU CAN CROSS CHECK THE ANSWER BY PUUTING THE VALUE OF X AND Y IN THE GIVEN EQUATIONS 

  • Question: Why HTTP is a connectionless protocol?

    Posted in: Computer Science | Date: 06/02/2018

    Answer:

    HTTP Protocol stands for Hyper Text Transfer Protocol HTTP is an access method (to access web pages) on the internet. It does not require the server to retain information or status about each user for the duration of multiple requests. This simplifies the contact between client and server.This simply means that the HTTP that is the backbone of the Web is unable to retain a memory of the identity of each client that connects to a Web site and therefore treats each request for a Web page as a unique and independent connection, with no relationship whatsoever to the connections that preceded it.

     

    HTTP is used by client to request the server for some information over the Web. The client establishes a connection with the server before sending a request. Over this connection only, the server returns the response to client. When the response is delivered, the connection between client and server is destroyed. By chance, if the same client would like to contact the same server again, the client should establish altogether a new connection. To put in a simple way, if the client would like to request the same server 100 times, the client should establish a new connection 100 times as the server closes the connection for each request when the response is delivered.

    HTTP Protocol was designed as connectionless for the reason, the server resources should be shared equally by all the clients throughout world. If one client holds the server with 100 requests, by all the requests are answered, the server cannot allocate time for other clients.

     

  • Answer:

    Underflow(A)

  • Answer:

    Overflow(A)

  • Question: Process of removing an element from stack is called __________

    Posted in: C,C++ | Date: 06/03/2018

    Answer:

    Pop(D)

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