MPT - 86164

Amulya K Male, 55 Years

Associated for 6 Years 6 Months
Class 11 - 12 Tutor

Activity Score - 543

Area: Lajpat Nagar
Location: Delhi, India
Qualification :
  • M.Sc (SAMBALPUR UNIVERSITY - 1990)
  • ( - 0)
  • Total Experience:
    28 Years
  • Hourly Fees:
    INR 600
Tutoring Experience :

Teaching both Chemistry and Mathematics. Concept teaching and then practice test on each topic. Also combined test for every three topics completed. Homeworks from reference books. In this way preparing the student outside of text book also. Helping those student preparing for engineering and medical entrance examinations

Tutoring Option :
I Can Manage Both
Tutoring Approach :

My approach will be depend on the student's needs and learning style. However my teaching is based on encouraging students to think for themselves, using real-world examples wherever possible. I usually focus on exam-style or past paper questions in order to check, practice and perfect the student's understanding and technique.

Teaches:
Class 9 - 10 Mathematics Physics Chemistry CBSE INR 600 / Hour
Class 11 - 12 Chemistry CBSE Board INR 600 / Hour
Class 6 - 8 Chemistry CBSE INR 600 / Hour
Online Tutoring
Prior Online Tutoring Experience?
No
Tuition Fees:
INR 500
Online Tutoring Experience :
Not yet
Online Tools Details :
I am registered in skype,but not having idea of setting on line tutoring.
Online Availability :
Any time can be settled after discussion
  • Answer:

    A spectrochemical series is a list of ligands ordered on ligand strength to modify the difference in energy between the d orbitals (Δ) called the ligand-field splitting parameter for ligands or the crystal-field splitting parameter, which is mainly reflected in differences in color of similar metal-ligand complexes.

    spectrochemical series listing of ligands

    I− < Br− <   SCN− < Cl− <S2−< NO3− < N3− < F− < OH− < C2O42− ≈ H2O < NCS− < CH3CN <  (pyridine) <edta < NH3 <  (ethylenediamine) <  (2,2'-bipyridine) < (1,10-phenanthroline) < NO2− < PPh3 < CN− < CO

    It is an experimentally determined series based on the absorption of light by complexes with different ligands.

    Ligands arranged on the left end of this spectrochemical series are generally regarded as weaker ligands and cannot cause forcible pairing of electrons within 3d level and thus form outer orbital octahedral complexes. On the other hand ligands lying at the right end are stronger ligands and form inner orbital octahedral complexes after forcible pairing of electrons within 3d level.

  • Answer:

    PRIMARY AMINES WITH TWO HYDROGEN CAN FORM TWO HYDROGEN BONDS IN WATER.AT THE SAME TIME

    TERTIARY AMINES DOES NOT HAVE HYDROGEN BONDINH DUE TO ABSENCE OF HYDROGEN.MORE THE HYDROGEN BONDING MORE IS THE BOILING POINT.THEREFORE PRIMARY AMINES HAVE MORE BOILING POINT THEN ERTIARY AMINES.

  • Question: name the two ambident nucleophile for me please.

    Posted in: Chemistry | Date: 24/10/2015

    Answer:

    -CN  AND -NO2 ARE THE TWO AMBIDENT NUCLEOPHILE. -CN CAN ATTACK THROUGH CARBON CENTRE OR THROUGH NIITROGEN CENTRE. -NO2 CAN ATTACK THROUGH NITROGEN AND OXYGEN OF -NO2.

  • Question: why are low spin tetrahedral complexes not formed?

    Posted in: Chemistry | Date: 24/10/2015

    Answer:

    IN TETRAHEDRAL COMPLEXES,SP3 HYBRIDISATION TAKES PLACE. THE 3D ORBITALS ARE UNTOUCHED.SO UNPAIRED ELECTRONS ARE AVAILABLE ALWAYS.SO THIS UNPAIRED ELECTRONS GIVES HIGH SPINS .THEREFORE LOW SPIN TETRAHEDRAL COMPLEXES ARE NOT FORMED.

    LOW SPIN SQUARE PLANAR COMPLEXES ARE POSSIBLE.

  • Answer:

    VITAMIN  B-12 IS A COBALT COMPLEX,HAEMOGLOBIN(BLOOD) IS A COMPLEX OF IRON,CHLOROPHILL IS A COMPLEX OF MAGNESIUM.

  • Answer:

    • CALCINATION IS A PROCESS OF HEATING CARBONATE ORE IN THE ABSENCE OF AIR TO CONVERT THE ORE INTO OXIDE FORM.     WHILE ROASTING IS A PROCESS OF HEATING SULPHIDE ORES IN A FURNACE WITH REGULAR SUPPLY OF AIR.TO CONVERT SULPHIDE ORES TO OXIDE ORES.
    •  

     

  • Question: How is pig iron converted into cast iron?

    Posted in: Chemistry | Date: 25/10/2015

    Answer:

    PIG IRON OBTAINED FROM BLAST FURNACE CONTAINS 4% CARBON.  CAST IRON IS MADE FROM PIG IRON BY MELTING PIG IRON WITH IRON SCRAP AND COKE AND BY PASSING HOT AIT BLAST INTO THE MIXTURE.

    CAST IRON HAS 3% CARBON CONTENT LOWER THAN PIG IRON.CAST IRON IS HARD AND BRITTLE.

  • Answer:

    LYOPHILLIC SOLS ARE FORMED DIRECTLY BY MIXING SUBSTANCES LIKE GUM, GELATINE, STARCH,RUBBER WITH A SUITABLE LIQUID CALL DISPERSION MEDIUM.IF THE DISPERSION MEDIUM OF THESE  SOLS ARE SEPARATED FROM THE DISPERSED PHASE,THE SOL CAN BE AGAIN MADE BY REMIXING WITH THE DISPERSION MEDIUM.THESE SOLS ARE CALLED REVERSIBLE SOL.

  • Answer:

    TRANSITION ELEMENT HAVE HIGH EFFECTIVE NUCLEAR CHARGE AND A LARGE NUMBER OF VALENCE ELECTRON. THEREFORE THEY FORM VERY STRONG METALLIC BONDS OR METAL METAL BONDING WHICH ARISES DUE TO UNPAIRED ELECTRONS IN THE (n-1) d-SUBSHELL.AS A RESULT THE ENTHALPY OF ATOMISATION OF TRANSITION ELEMENT IS HIGH.

  • Question: define hydrosol

    Posted in: Chemistry | Date: 26/10/2015

    Answer:

    "Hydrosols are the condensate water coproduced during the steam- or hydro-distillation of plant material for aromatherapeutic purposes.

    A hydrosol is the aromatic water that remains after steam-distilling or hydro-distilling botanical material such as lavender or organic flora matter

  • Answer:

    ACTIVATED CHARCOAL HAS THE PROPERTY OF ADSORBING GAS PARTICLES.AS COAL MINES HAVE MANY HARMFUL GASES,SO WORKERS USE GAS MASK WITH ACTIVATED CHARCOAL,SO THAT THE MASK WILL ADSORB ALL HAMFUL GASES AND LEAVE PURE AIR PARTICLES.

  • Answer:

    Artificial rain is produced by seeding clouds artificially with ‘dry ice’ (frozen carbon dioxide), silver iodide, or other appropriate particles, which act as condensation nuclei.Where there is cloud but condensation is not taking place then this artificial rain method is used.

    The principle used is coagulation . It is a principle of aggregating together the colloidal particle so as to change them into large sized particle which ultimately settle as a precipitate.

     

     

     

     

     

  • Question: what is the composition of collodion? please tell

    Posted in: Chemistry | Date: 26/10/2015

    Answer:

    The composition of collodion is cellulose nitrate , flash paper, and gun cotton  in ether and alcohol.

  • Question: what happens when gelatin is mixed with gold sol?

    Posted in: Chemistry | Date: 26/10/2015

    Answer:

    Gold sol is a lyophobic sol, an unstable sol. Addition of gelatin stabilises the sol.

  • Answer:

    ONLY 2 ISOMERS  1-chloro-2,3-Dimethylbutane  and  2-chloro-2,3-dimethylbutane would result in the desired product.

  • Answer:

    Only by the PV=nRT .Mass of 1L of steam=0.0006*1000=.6g

    No.of moles of steam= .6g/18g== 1/30 moles

    Volume=V =nRT/P== (1/30) (0.083)(373)/1==1.032 Litre

  • Answer:

    X2O5  BECAUSE THE RATIO OF X:O IN THE OXIDE WILL BE .4:1

  • Question: Please answer this

    Posted in: Chemistry | Date: 21/06/2018

    Answer:

    Your question is wrong. This type of question can be answered like this.

    Let the mol.wt. of M be x g. so mol wt of the compound is (x+142)

    x+142 g of compound contain 142 g of chlorine

    so 25 g of compound will form  (142/(x+142))*25 .This is the answer.You are given with 0.54 g of chlorine which is not possible.

     

  • Answer:

    AMMONIA GAS WNEN PASSED THROUGH WATER IT FORMS AMMONIUM HYDROXIDE WHICH IS A BASE.

    SO IN AQUOUS MEDIUM AMMONIA ACTS AS A BASE.

    NH3+H20------NH4OH

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