MPT - 331973

Siva P Male, 23 Years

Associated for 1 Year 8 Months
Results Assured
Class 11 - 12 Tutor

Activity Score - 345

  • I go to Student's Home
Location: Bangalore, India
Qualification :
  • B.Tech/B.E. (NIT calicut - 2017)
  • Total Experience:
    1 Year
  • Hourly Fees:
    INR 160
Tutoring Experience :

An experienced tutor who can teach physics and mathematics as well as advanced mechanical subjects in the best way possible with real life examples. Medium of teaching : English

Tutoring Option :
Home Tuition Only
Tutoring Approach :

I wouldn't go for an hourly approach whille teaching rather I would teach until the student understands the concept and I can give suggestions on how to approach for competitive exams.

Class 9 - 10 Mathematics Physics Algebra All Boards INR 150 / Hour
Class 11 - 12 Mathematics Physics CBSE Board INR 160 / Hour
Engineering Entrance & IITJEE Physics IIT JEE Mains AIEEE INR 170 / Hour
Engineering Subjects Mechanical INR 180 / Hour
Class 6 - 8 Mathematics Physics All Boards INR 150 / Hour
Basic Computer / Office MS Office INR 150 / Hour

2 Notes written by me

  • Etiquette In Technology

    Files: 1

    2 times downloaded

    How to text someone? How to talk on the phone? How to write an email?

  • Wind Based Water Pump

    Files: 1

    9 times downloaded

    Water Pump Using Renewable Energy Like Wind!


2 Presentations prepared by me

  • Wind Based Water Pump

    16 times downloaded

  • Recycling Of Plastics

    182 times downloaded

  • Question: An arbitrary vector v can be expressed as 

    Posted in: Physics | Date: 09/01/2018


    It is option D

    Any vector can be expressed as a sum of 3 perpendicular unit vectors, each multiplied by some number(the component of vector along that axis)

    In the picture attached, the vector a has 3 different components along 3 perpendicular axes x,y,z and these components need not be equal all the times

  • Question: Which of the following statements false?

    Posted in: Physics | Date: 09/01/2018


    Only false statement is : Option (C)

    In the image attached it is clear that distance(total path length) is greater than displacement. Rest of the options are true.




  • Question: Which is a constant for a freely falling object?

    Posted in: Physics | Date: 09/01/2018


    For a freely falling body, there no other forces acting on the body other than gravity. (If you assume that there is no air resistance). The gravity force is nothing but the weight of the body which is constant. Since Force = mass * acceleration and mass is constant, so acceleration due to gravity is constant which is 9.81 m/s^2

    Displacement, Velocity and speed increases as it falls but acceleration due to gravity is constant for earth

  • Question: Vectors can be added by

    Posted in: Physics | Date: 09/01/2018


    Option C

    Vector addition is the right way to add any number of vectors

    In vector addition, we add the magnitudes of each unit vector separately

    The same applies for the subtraction also which is shown in figure

  • Answer:

    Assumptions : No effect of air, gravity change due to height

    Force = mg = 0.002*10 = 0.02 N     (since 2 g = 0.002 kg)

    Displacement = height = 1km = 1000 m

    Work done = Force * displacement 

    Work done = 0.02*1000 = 20 N.m

    Note : in the question the velocity which is mentioned is 50 m/s but since it is given in the question that g value is 10m/s^2 which is constant , the velocity should be = sqrt(2gh) = sqrt(2*10*1000) = 141.4 m/s

  • Question: Which of the following physical quantities a scalar? 

    Posted in: Physics | Date: 09/01/2018


    Option B

    Linear momentum = mass*velocity and all the velocities are vector quantities,

    so linear momentum is also a vector (since mass is scalar)

    But for current flowing in a wire we mention just a number (like 2 Amperes) but not the direction

  • Answer:

    Assumptions : No effect of air, gravity change due to height

    Force = mg = 0.002*10 = 0.02 N     (since 2 g = 0.002 kg)

    Displacement = height = 1km = 1000 m

    Work done = Force * displacement 

    Work done = 0.02*1000 = 20 N.m

  • Answer:

    Potential energy of bob is converted to kinetic energy and the energy lost during transition is 5%

    Total energy intially =  mgh

    Total energy final = 0.5*mv^2

    Energy lost = 5% of mgh = 0.05*mgh

    So intial energy = final energy + loss

    • mgh = 0.5*mv^2 + 0.05*mgh
    • 0.95*mgh = 0.5*mv^2
    • 0.475*gh = v^2 (since g=10, h=1.5)
    • v = sqrt (0.475*10*1.5) = 2.67 m/s

  • Answer:

    Given flow rate = 30 m^3 in 15 min = 2 m^3/min = 1/30 m^3/s

    mass flow rate = vol. flow rate*density = 1/30 * 1000 = 100/3 kg/s

    Power required = (mass flow rate)*g*h = 100/3*10*40 = 40000/3 Watts = 40/3 kW

    But since efficiency is 30% - (if 100 W is consumed only 30 W will be supplied)

    Total power consumed = power required/efficiency = (40/3)/0.3 = 44.44 kW


  • Answer:

    Answer : 2m/s

    The formulas for velocities after collision is mentioned in the picture

    Thumbrule : If 2 equal masses collide with each other with v1, v2 velocities then their final velocities will be exchanged

  • Answer:

    Option D

    Speed = distance/time

    since the question has instantaneous speed as constant, it means distance covered(path) in a time is constant / equal

    rest of the options are related to velocity but not speed

  • Answer:

    Boyle's law holds true for a system if there is no addition of energy i.e PV=constant

    In this case we are doing some work to pump air into the tyre so the energy is added into the system and thus the temperature will also increase inside the tyre and boyle's law is applied for constant temperature only

  • Answer:

    So membrane tension is 5 N/m which is given to find the pressure inside the sphere. The figure shows the forces along the membrane and pressure inside sphere

    So the force by membrane = 2*pi*R*sigma = 2*pi*8*5 = 80*pi N

    Force by the pressure inside = Area*Pressure = pi*R*R*P

    • => pi*8*8*P = 80*pi
    • => P = 5/4 N/m^2  which is gauge pressure but not absolute pressure
    • => Pabs = 5/4 + 1.013*10^5 Pa which is absolute pressure

    Now use the formula PM = dRT

    Now use the Pabs found and substitute to find density d          (T is in kelvins)

    M for air = 28.97 g/mol 

    Similarly, find the density of air outside balloon and find the buoyancy force acting on balloon and subtract buoyancy with weight of ballon then you will the weight it can carry


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