I
• Female, 55 Years
• Activity Score115

## Indrani K

Associated for 1 Year 8 Months
• I teach at My Home
• Online
• Qualification:
M.Sc, Ph.D
• Experience:
I am working with students training for past 30 years, having passed out from IIT Mumbai I have a zeal for making students enjoy learning especially Mathematics, communication skills and presentation skills.
• Teaches:
UGC Net, Slow Learners, Learning Disabilities, Mathematics, Bank PO, PSU Exam, Spoken English, Effective Communication, Public Speaking, Corporate Communication, Personality Development, Communicative English, Mental Mathematics, Handwriting
• Areas:
• Pincode:
560090
Profile Details

#### Qualification :

 M.Sc I I T Mumbai 1986 Ph.D Mahila University, Tirupati 2006

I am working with students training for past 30 years, having passed out from IIT Mumbai I have a zeal for making students enjoy learning especially Mathematics, communication skills and presentation skills.

#### Tutoring Option:

Home Tuition Only

#### Tutoring Approach:

I would be giving practical applications and need for learning first, explain with complete details and then test whether student has understood the concept well.

#### Hourly Fees [INR]:

1000.00

 English Speaking Public Speaking, Spoken English, Effective Communication, Corporate Communication INR 1500.00 /hour Engineering Subjects Mathematics INR 2000.00 /hour Test Preparation UGC Net INR 1000.00 /hour Special Education Learning Disabilities, Slow Learners INR 1000.00 /hour Academic Enrichment Handwriting, Personality Development, Mental Mathematics, Communicative English INR 1000.00 /hour Competitive Exams Bank PO, PSU Exam INR 1000.00 /hour
Educational Resources

## Presentations prepared by me [1]

##### Differential Equations

Differential Equations Notes and explanation for First year Engineering students

• ## Question: In an examination it is required to get 900 marks of the aggregate marks to pass...

Posted in: Bank PO | Date: 06/02/2018

Suppose x is the aggregate amount then given that

900 - 43% of x = 40

860 = 0.43 x

2000 = x

• ## Question: Is it possible for a student to give a good speech in class without any preparat...

Posted in: Communicative English,Effective Communication,Speech & Drama,Bengali,Assamese,Accent Training | Date: 06/02/2018

Yes, it is possible only for those students who have been reading well, who have developed a good vocabulary, who have a good articulation skill and confidence. Information required for a good speech is collected by a students by a regular practicve of reading good books, news paper and being aware of current affairs.

• ## Question: Ravi borrows a sum of Rs.3000 at the beginning of a year. After four months Rs.4...

Posted in: Bank PO | Date: 06/02/2018

For the sum Rs 3000 with rate of interest r the interest for one year is (3000 x 1x r)/100 = 30 r

For the sum Rs 4200 with rate of interest 2r the interest for 8 months is (4200 x 8/12 x 2r)/100 = 56 r

Total interest = 30 r + 56 r = 86 r = 832 => r = 832 / 86 = 9.6744

• ## Question: A Raghu borrowed 50000 from two money lenders . For the first loan, he paid 28% ...

Posted in: Bank PO | Date: 06/02/2018

Ans:- 14000 & 36000

Sol:- Let Raghu borrowed x from first money lender and (50000-x) from second money lender

Given that Total SI=  SI of first +  SI of second = 12560

x*28*1/100 + (50000-x)*24*1/100=12560

28 x - 24 x = 12560*100 - 50000*24

4x =56000

x=14000

so (50000-x) =  36000

• ## Question: The age of the father 3 years ago was 7 times the age of his son. At present the...

Posted in: Bank PO | Date: 06/02/2018

Let the present age of Father be x and son be y.

Given that x = 5 y ................................(1)

Three years ago x - 3 = 7 (y - 3)...........(2)

Substituting from equation (1) in to (2) we get

5 y - 3 = 7 y - 21

21 - 3 = 7 y - 5 y

18 = 2 y

y = 9

=> x = 45

So at present Father age is 45 and son age is 9

• ## Question: Three years earlier the father was 7 times as old as his son. Three years hence ...

Posted in: Bank PO | Date: 06/02/2018

Answer : Fathyer age 45, son age 9 at present

Let the present age of father be x and son be y

Thre years ago x - 3 = 7 (y - 3) => x = 7y - 18 .................(1)

Three years after x + 3 = 4 (y + 3) ..................................(2)

Substituting from (1) into (2) we get

7y - 18 + 3 = 4y + 12

7y - 4y = 12 + 15

3 y = 27

y = 9 => x = 9 * 7 - 18 = 45

Hence  present age of father is 45 and son is 9 yrs

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