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Question: A sum amount rupees 7458 in 4 years and rupees 8362 in 6 years at a certain rate of simple interest find the sum

Posted by: Yogasri on 12.11.2022

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Answer:

Ans. The Sum of money is Rs. 5650

Explanation: Here, we see, interest in (6-4) = 2 years = Rs. (8362 - 7458) = Rs. 904.

So, interest in 4 years = Rs. 904 x 2 = Rs. 1808.

Hence, the sum of money = Amount in 4 years - Interest in 4 years = Rs. (7458 - 1808) = Rs. 5650.

Answer:

Answer:

Let the principal = Rs 100 and rate of interest per year = Rs x

Then principal plus 4 year interest = 100+ 4x  = Rs 7458

Similarly principal plus 6 year interest = 100+6x = Rs 8362

Therefore  interest for 2 years =  2x =Rs 8362 - Rs 7458= Rs 904

Hence interest per year = x = 904/2 = Rs 452

For Rs x interest per year , principal = Rs 100

For Rs 452  interest per year ,  principal = P =  (452/x) *100  =45200/x

Sum on principal of Rs (45200/x)  for 4 years =  (45200/x) + (45200/x) *4x/100 = Rs 7458

That is (45200/x ) +1808 = 7458  or ( 45200/x)  = P=  7458-1808 = 5650

Hence principal = Rs 5650

Answer:
Let, Principal=x Interest of 1 year=y Then, X+4y=7458 eq1 X+6y=8362 eq2 Subtract eq 1from eq 2 You get 2y=904 4y=1808 From eq 1 X+1808=7458 X=7458-1808 X=5650
Answer:
Let, Principal=x Interest of 1 year=y Then, X+4y=7458 eq1 X+6y=8362 eq2 Subtract eq 1from eq 2 You get 2y=904 4y=1808 From eq 1 X+1808=7458 X=7458-1808 X=5650 Rate of interest for 4 year=1808/5650×100 =32% Rate of interest for one year =32÷4 = 8%p.a.
Answer:

x=sum; y=rate of interest

as per problem,

x(1+4y)=7458........(1)

x(1+6y)=8362.......(2)

3*(1)-2*(2) gives

x=5650

x= sum=5650.Ans.

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