Let the distance between points P&Q be considered as 1 unit..
As both persons take same time of 6 hours to travel this distance their speeds are same
And each will travel in 1 hr = 1/6 of the distance. The person at P starts 1 hr earlier
(at 5 AM) than the other person at Q .Therefore the person at P would have traveled
a distance of 1/6 of the distance between P&Q by 6AM.
Therefore the distance between them when person from Q starts at 6 Am
= 5/6 of the distance between P&Q.
The person from P will take 5 hrs to cover this distance of 5/6 parts. As the person from Q also travels with the same speed towards P both the persons will meet each other midway,that is both will travel 5/2 = 2 ½ hours to meet each other.
Hence the person from Q will meet the person from P= at 6AM +2 ½ hrs = 8 Hrs 30 minutes
The person from Q would have traveled a distance of (5/2)*(1/6) = 5/12 part of distance PQ