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Answer:

For the quadratic equation  ax^2+ bx+c =0, the sum of the roots=  -b/a; that is sum of the roots= 

  negative  coefficient of x/ co efficient of x^2 .

Here the quadratic equation is 2x^2 -6kx+6x-7 =0. that is 2x^2 -6(k-1)x - 7 = 0

Thetfore  sum of the roots =   6(k-1)/2 = 3(k-1). As one root is the negative of the other the sum of the roots = 0

Hence3(k-1) = 0 or k=1

Therfore k=1

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