Delhi
Posted by: on 29.04.2021
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Answer:
For the quadratic equation ax^2+ bx+c =0, the sum of the roots= -b/a; that is sum of the roots=
negative coefficient of x/ co efficient of x^2 .
Here the quadratic equation is 2x^2 -6kx+6x-7 =0. that is 2x^2 -6(k-1)x - 7 = 0
Thetfore sum of the roots = 6(k-1)/2 = 3(k-1). As one root is the negative of the other the sum of the roots = 0
Hence3(k-1) = 0 or k=1
Therfore k=1
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