Question: Anil is able to double his money in 3 years how much ROI is he getting yearly.

Posted by: Anurag on 30.03.2021

Let the principal be Rs x and then the amount after three years will be Rs 2x SI = Amount - Principal =2x - x = x SI = P*R*T/100 x = x*R*3/100 x*100/3x = R R = 100/3 = 33.333 %
Let, P=₹100, therefore A=₹200, SI=A-P=₹200-₹100=100, therefore, R = (SI×100)/(P×T)=(100×100)/(100×3)=100/3%= 33 and half%

P=X

R=?

T=3 YEARS

SI= X

SI=P*R*T/100

X=X*R*3/100

R=100/3=33.33%

ATP, SI = P in 3 yrs.

So, P = (P.R.3)/100 .   => R = 100/3% = 33.33% .

Ans. ROI = 33.33% p.a.

Let Principal = x Given Amount = 2x Time = 3 years Rate of interest = r Simple interest = Amount -Principal I.e. SI = 2x-x Or SI = x As per the formula of Simple interest, SI = (Principal×Time×Rate)/100 I.e. x = (x×r×3)/100 We will take x on left hand side, we get x/x=(r×3)/100 Which gives 1=(r×3)/100 On simplifying r×3=100 r=100/3 Hence the Rate of interest = 33.3% per annum

Let principal amount P=x;

then A=2x

time=3 years

rate r= ?

or simple interest s.i.= A-p=2x-x=x;

formula simple inetest= (P*time*rate)/100;

put values  x=(x*3*r)/100;

or x/x=3r/100; (transposing of x from r.h.s to l.h.s.

or r=100/3;

or r=33.33;

so the ROI is 33.33%

Let, P=x Then, according to the question the A will be equal to 2x We know, A=P+I ; or, 2x=x +I; I=x We know, I=(Prt)/100 or, r=(100I)/Pt or, r= (100*x)/(x*3) or, r= 33.3%

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