  Question: If (x-2) is a factor of polynomial f(x) but not of g(x), then it must be a factor of? a)f(x) g(x) , b)g(x)-f(x) , c) f(x)-g(x) , d) {f(x)+g(x)}g(x)

Posted by: Suyash D. on 14.03.2021 Shubham B. from Kolkata
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(x-2) is a factor of f(x), which again is a factor of f(x).g(x). Hence, (x-2) is a factor of f(x).g(x). Thus, answer is option (A) f(x).g(x). Shubham B. from Kolkata
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(x-2) is a factor of f(x), which again is a factor of f(x).g(x). Hence, (x-2) is a factor of f(x).g(x). Thus, answer is option (A) f(x).g(x).
S
Sakshi from Gurgaon
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A) f(x) g(x) is the only function where x-2 can be taken common from the function as all the other functions contain f(x) either in addition or subtraction to g(x) and thus can't be taken common completely. S.Chandra from Kolkata
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Ans. Option a) f(x).g(x)

Reason: f(x).g(x) is the only polynomial given, which already contains the factor (x-2). Rathindra N. from Kolkata
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Ans: option (a), as (x-2) is a factor of f(x) as well as f(x).g(x) which is divisible by (x-2) although (x-2) is not a factor of g(x). Pankaj S. from Delhi
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Ans -a. f (x) g(x) • Like

Answer:  It is given that (x-2) is a factor of  f(x) but not a factor of  g(x). This means that (x-2)  is not a common  factor between  f(x) and g(x). In that case (x-2) can only be a factor of  f(x)*g(x) or f(x) /g(x). Out of the four options given only option (a) satisfies this condition. Hence the correct  answer is option (a).

G
Gaurav S. from Noida
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A
Anoop S. from Jaipur
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If x-2 is a facor of f(x) but not g(x), it means f(x) must contain (x-2) term in it as

f(x)=(x-2)f1(x) but g(x ) dos not contain any facor of (x-2)

so when f(x) is multiply anyone its alsohas a factor of x-2.

i.e. f(x)g(x) has factor of (x-2) and

so final answer is Option A

A
Anjitha S. from Kochi
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if (x -2) is a factor of polynomial f(x) but not of g(x),then it must be a factor of multiplication of f(x) and g(x). i.e f(x)g(x). Himanshu B. from Mumbai
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• Answer ( A) F(x) * G(x)  for explanation see the attached file. P
Pravat S. from Bangalore
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A) f(x)g(x) F(x) can be written as (x-2) h(x) So f(x)g(x) =(x-2)h(x)g(x) So f(x)g(x)/(x-2) = (x-2)h(x)g(x)/(x-2) = h(x)g(x) Divisible by (x-2)

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