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Question: A body is allowed to fall freely. The ratio of its displacement in 1,2 and 3 seconds is
• A
1:4:9
• B
1:2:3
• C
1:3:5
• D
1:9:25

Posted by: Arhaan on 02.02.2021

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• Answered by: Dr. J. from Mumbai
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Answer:
Here u=0 and s=1/2 gt^2 so the ratio is (1:4:9)
• Answered by: Rathindra N. from Kolkata
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Answer:
Ratio of displacement in 1s,2s and 3s=1^2:2^2:3^2=1:4:9
• Answered by: Rathindra N. from Kolkata
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Answer:
1:4:9 as displacement directly proportional to the square of time.
• Answered by: Chhaya R. from Noida
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Answer:
Option A = 1:4:9 • Answered by: Vijay D. from Pune
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Answer:
As kinematical equation S=ut+1/2 at^2 In free fall it is Directly proportion to square of time S1:S2:S3= 1^2:2^2:3^2 =1:4:9
• Answered by:
A
Ariba S. from Delhi
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Answer:
In free fall motion, displacement of body is directly proportional to the square of time. We get this from S=(1/2)gt². So the ratio of displacement for time 1:2:3::1²:2²:3² i. e. 1:4:9
• Answered by: Saloni T. from Jamshedpur
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Answer:
If the question is ratio between 1st,2nd and 3rd second - 1:3:5 If the question is in 1sec:2sec:3sec - 1:4:9
• Answered by: S.Chandra from Kolkata
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Answer:

The displacement varies as square of time for a freely falling body. Here, the 'g' remaining same, the ratio of the displacements of the body after 1, 2 and 3 seconds will be 1^2:2^2:3^2 = 1:4:9 . So, option A - 1:4:9 is correct

• Answered by: Venkata J. from Hyderabad
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Answer:

body falling freely , displacement is proportional to square of time d=gt^2/2 ,  This gives 1,4,9 . (squre of time)

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