Delhi
Posted by: Pavan on 03.12.2020
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Here I attached the file.
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Answer:
Given f(x) = e^(ax+b). Differentiating with respect to x we get
dy/dx= f'(x) = a*e^(ax+b). Again differentiating with nrespect to x we get
d/dx(dy/dx)= f"(x) = a*a*e^(ax+b) = a^2*e^(ax+b). Continuing upto n times we get
nth derivative of f(x) = a^n* e^(ax+b)
f(x) =e^(ax+b)
f'(x) =ae^(ax+b)
f''(x) =a^2 e^(ax+b)
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f^n (x) =a^n e^(ax+b)
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