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What's Your Question?
Answer

Sin3X=Cos2X

Cos(90-3X)=Cos2X

90-3X=2X

5X=90

X=18

Answer

sin 3x = sin( 360k + 90 - 2x )

3x = 360k + 90 -2x 

x = 72k+18

x = 90, 162

another solution is 

sin (-3x) = cos( - 2x )

sin (-3x + 360k) = sin(  180 + 90 - 2x )

x =360k-270

x = 90

So we have only two solutions : 90, 162

Answer
Ok now, i want no.of solutions b/w given interval
Answer
Sin3x =cos2x Sin3x= sin(90-2x) 3x=90-2x 3x+2x=90 5x=90 X=14

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