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Volume of Alcohol Remaining after n times \(= v × (1- 1/5)^n = v × (4/5)^n\)
After 5 times in succession i.e. for n = 5,

 Volume of Alcohol Remaining \(= {v × (4/5)^5 }= {1024v\over3125}\)

∴Alcohol is removed from the vessel =\(({ v} –{ 1024v\over3125} )\)
\( = {2101v\over3125}\)

Therfore, the alcohol originally contained in the vessel will have been removed from it = \(2101\over3125\)

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