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Let the man's rate upstream be x kmph and that downstream be y kmph. Then, distance covered upstream in 8 hrs 48 min = Distance covered downstream in 4 hrs. x *8 4/5 = (y x 4) 44/5 x =4y y = 11/5x. Required ratio = (y + x)/2 : (y - x)/2 = (16x/5* 1/2) : (6x /5* 1/2) = 8/5: 3/5 = 8 : 3.
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 The reqd. ratio between the speed of the boat and that of water current is 8:3 

Taking, spped of boat as x and speed of current as y,

x + y = d/240 

x - y = d/528

(x+y)/(x - y) = 528/240

x/y = 768/288 = 8/3

Answer

Let speed of boat be b and speed of current be c

ATP, b+c= d/240. and b-c= d/528.

adding both,we get, b=768, c= 288.

so, b/c= 768/288= 8/3.

Answer

Ans. The reqd. ratio between the speed of the boat and that of water current is 8:3 

Taking, spped of boat as x and speed of current as y,

x + y = d/240 

x - y = d/528

(x+y)/(x - y) = 528/240

x/y = 768/288 = 8/3

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