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We know distance travelled s= ut + 0.5at^2, where u=initial velcity=0; as body started from rest, a=constant acceleration, t=time .  S1= (0)t+0.5a(10)^2= 50a. Volocity after initial 10 seconds,V= u +at = 0 + 10a =10a

Distance traveled in the last 10 secs, S2= v(10) + 0.5a(10)^2= 10a(10) + 50a = 150a = 3S1 Option B

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