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Answer

Answer is A , 32m

Firstly , v = u + a.t,

now

v=0m, u=16m and t=4 sec

we get a = -4 m per (s^2)

then, applying 

v^2 = u^2 - 2.a.s , we get

s = 32 m 

Answer

ANS--A

First applying, v = u + a.t,

Here v=0, u=16 and t=4 sec

we get a = -4 m/s^2

Again applying v^2 = u^2 - 2.a.s , we get, s = 32 m 

Answer

Answer should be A.

As it is mentioned that the car is brought to rest uniformly, the retardation ( negative acceleration) is constant.

 

Answer

answer is A 32m.  

from v=u+at,we got the value of acceleration,{a}

then,by 2as=v^2-u^2

Answer

Ans. Option A (32 m)

First applying, v = u - a.t, we get a = 4 m/s^2

Again applying v^2 = u^2 - 2.a.s , we get, s = 32 m 

 

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