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compoubd interst=10*10         11*11

                              100             121                    (121-100=21 compound interst)

ci=21/100=420/x where x=principle

x= 2000

si p*r*t/100=2000*10*3/100=600 ans

 

Answer

ANS--C

Let, SI for 1yr be Rs. x .

ATP, x(1 + 10/100)^1 = 420 - x  [i.e. the CI for 2nd yr only]

By solving, x = 200

Hence, reqd. SI = Rs. 400*3/2 = Rs. 600

Answer

Ans. Option C (Rs. 600)

Let, SI for 1yr be Rs. x .

ATP, x(1 + 10/100)^1 = 420 - x  [i.e. the CI for 2nd yr only]

By solving, x = 200

Hence, reqd. SI = Rs. 400*3/2 = Rs. 600  .  Ans.

 

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