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Answer

Supposing distance between tower and chimney to be d, we have tan60•= h/d

=> d= h/√3.

Again, tan30= (h-40)/d

=> d= √3((h-40)

Comparing values of d,we find h= 60m

Now,h is the height of chimney over the tower and the tower height is given to be 40m. Then, chimney height is 40+60=100m.

Thus,it meets the requisite pollution norms of height.

Answer

Let d be the distance between tower and chimney.  Then tan 60 = h/d where h is height of tower.

Also tan 30 = (h-40)/d

Dividing 3 = h/(h-40) Or 3h-120 = h

h = 60 m.

Height is less than 60 hence meets pollution norms.

Answer

Let d be the distance between tower and chimney.  Then tan 60 = h/d where h is height of tower.

Also tan 30 = (h-40)/d

Dividing 3 = h/(h-40) Or 3h-120 = h

h = 60 m.

Height is less than 60 hence meets pollution norms.

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