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Question:

Two equal resistances R$_{1}$ = R$_{2}$= R are connected with a 30 $\Omega$ resistor and a battery of terminal voltage V. The currents in the two branches are 2.25 A and 1.5 A as shown in the figure. Then, what will happen? Please explain the answer in brief.

• A

R$_{2}$= 15$\Omega$

• B

R$_{2}$ = 30$\Omega$

• C

V = 36 V

• D

V = 180 V

Posted by: Srivastava 7 months ago

• From:Chennai
• Date: 08.10.2017

Answer A. R2 = 15 Ohm

Total Current is 2.25 A.

The current through the 30 ohm resister is 1.5 A.

Hence Current through the R2 should be equal to 0.75 A (2.25-1.5 = 0.75 A)

If R2 is taken as Unknown, Then  R2 is given by,

By Current didsion method, 1.5  = 2.25 x 30 / (30+R2)

1.5 x (30+R2) = 67.5

45 + 1.5 R2 = 67.5

1.5 R2 = 67.5 - 45

R2 = 22.5 / 1.5

R2 = 15 Ohm

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