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Question:

If an organic compound contains 49.3% carbon and 6.84% hydrogen, and its vapour density is 73 g/L. Then the molecular formula of the compound is........ Please explain the correct answer.

• A

C$_{3}$H$_{8}$O$_{2}$

• B

C$_{3}$H$_{10}$O$_{2}$

• C

C$_{6}$H$_{9}$O

• D

C$_{6}$H$_{10}$O$_{4}$

Posted by: P. T. 7 months ago

• From:Kolkata
• Date: 07.10.2017

Ans, Option D - C6H10O4

In the compound, Weight of Carbon = 72 g (approx), weight of Hydrogen = 10 g (approx), weight of Oxygen = 64 g (approx) .

Respective atomic masses of C, H and O are 12, 1 and 16.

So, atoms of C, H and O combined are 72/12 = 6; 10/1 = 10 and 64/16 = 4 respectively.

Hence, the formula.

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