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Increasing [E] lowers [C] by a simple application of Le Chatelier's Principle. Regarding the effect of increasing [E] on [A], your understanding is correct. To make your observation more obvious, we may reverse reaction (ii) and add it to reaction (i): A(g)+E(g)↽−−⇀B(g)+D(g) So we can, once again, simply apply Le Chatelier's Principle and see that increasing [E] lowers [A].
Answer
by common ion effect.

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