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(i) We know that the acceleration or retardation due to gravity  does nor depend  upon the mass of the bodies The distance travelled by a body under the influence of gravity depends only on the initial speed. As both the balls  are thrown vertically upwards with the same initial velocity , both will reach the same height.

(ii) Let the initial velocity of the body = u  Let the final velocity =v

Let uniform acceleration on the body =  a

Then the instantaneous velocity v(t) of the body at any instant “t” =  u+a*t   ……….A

The average velocity of the body =  (u+v)/2

From equation A, time “t” taken to reach the final velocity   = (v-u) / a

As the body is travelling with uniform acceleration, the body will attain the average velocity of (u+v) / 2  in half time , that is in “t/2” seconds. But  t/2 = (v-u) / (2a)

Hence instantaneous velocity v(t) when t = t/2 seconds =  u+a (v-u) / (2a) =  u + { (v - u)/2}=

u+ (v/2) - (u/2) = (u+v)/2  

The instantaneous velocity will equal the  average velocity at Halftime

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