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Answer

Angle AOB=60°

Angle ACB =30°

Answer

Ans. i) <AOB = 60°  ; <ACB = 30°

Here, in â–³AOB, we know, OA = OB [since, radii of same circle]

But, OA = AB (given).  Thus, â–³AOB is an equilateral triangle. 

So, <AOB = 60°.

Again, <ACB = (1/2)of <AOB [since, angle at the centre is twice the angle at the circumference subtended by the same arc]

So, <ACB = 30°.

Answer

angle AOB = 60 degree

angle ACB = 30 degree

Answer

In the given circle 

O is the centre 

OA=OB (radius of the circle) -----i)

Given, OA=AB -------ii)

From i) & ii) OA=OB=AB

Since, OA,OB,AB are the sides of ∆ABO and OA=OB=AB

∆ABO is an equilateral triangle 

Hence, all interior angles are equal and each interior angles is 60°

Hence, angle AOB = angle ABO = angel BAO = 60°

angle AOB = 2xangle ACB

60°= 2x angle ACB

Angle ACB = 30°

Therefore 

angle AOB= 60°

angle ACB= 30°

Answer

60  degree

30 degree

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