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Answer

Given that 

f(x) = x+3,

g(x) = x-4 

h(x ) = 2x

I) hof(x) = h(f(x))

              = h(x+3) = 2(x+3) = 2x+6

ii) gof(x) = g(f(x) = g(x+3)

= x+3-4 = x-1 

iii) gofoh(x) = g[f(h(x)] = g[f(2x)]

 = g(2x+3) =2x+3-4

= 2x-1

iv) fogoh(x) = f[g[h(x) ]

= f[g(2x)]

 = f[2x-4] =2x-4+3

 = 2x-1

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