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Sl.no. Class interval. Frequency Cumulaative frequency 1. 0- 10. 5. 5 2. 10-20. x. x+5 3. 20-30. 20. x+25 4. 30-40. 15. x+40 5. 40-50. y. x+y+40 6. 50-60. 5. x+y+45 It is given that the total of observations n= 60. So n/ 2 = 60/2 = 30 Therefore the median class that includes the 30th observation will be the class interval 20-30 whose cumulative frequency is x+25. Now the formula for median m = l+{(n/2 - cf)/f}/*h , where l = lower limit of median class cf = cumulative frequency of the class preceding the median class f = frequency of the median class and h = class interval It is given that m = 30 then putting the required values in the above formula we get 30=. 20+[{30 -(x+5)}/20]*10= 20+(300/20) -(x+5)*(10/20) = 35 -(x+5)/2. That is 30= 35-(x+5)/2. or (x+5)/2 = 5. Therefore x+5 = 10.So we get x = 5. Now total cumulative frequency from the above table = 45+x+y and this is equal total number of observations 60. So 45+x+y = n= 60. That is 45+5 + y = 60 or y = 60- 50= 10 Hence x = 5 and y = 10

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