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INITIAL CONCENTRATION = 125 LITRES

REPLACED CONCENTRATION = 25 LITRES

 FINAL CONCENTRATION = INITIAL (1- REPLACED/INITIAL)^3                  [AS THIS METHOD WAS DONE FOR 3 TIMES]

                                            = 125 ( 1 - 25/125)^3

                                           = 125 ( 100/125)^3

                           ON SOLVING THIS YOU WILL GET   64 LITRES......WHICH IS MILK 

       AND REMAINING   61 LITRES WILL BE WATER . 

 

 

 

Answer
Initially, the quantity of milk in container= 125l Now, if 25L is taken out The quantity of milk in the container remains 100L. Again, if 25 l is taken out, it not only contains milk but also water. So the taken 25l contains (25*(25/125)) water. i e., 5l And the remained 100l contains (100*(25/125)) water. i. e., 20l The quantities taken out are 20l milk and 5l water. The remained quantities contain 80l milk and 20l water. After replacing the taken-out quantities with water, The updated quantities are 80l milk+(20+25=45)l water. The same algorithm is followed further for 2 repetitions. Finally, the container contains 64l of milk and 61l of water. There is a short cut for the question,which is given in the uploaded file

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