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Answer:

 Reading of voltmeter V1 =  1 Volt.
Percentage error in the reading = ± 5%

Absolute error =1*(± 5%) =  ±0.05volts

Therefore  the voltage reading of V1 will be between 0.95 - 1.05 Volts

 Reading of voltmeter V2 = 1.1 Volts

Percentage error = ± 5%

Absolute error = 1.1*(± 5%) =  ± 0.055 Volts

Therefore the voltage reading of  V2 will be between 1.045 - 1.155 Volts

Now difference V1-V2 =  -(V2-V1)

V2-V1 will be maximum when V2 is maximum and V1 is minimum

Therefore maximum value of  V2-V1 =  1.155 - 0.95 =  0.205 volts

Correct  Value of V2-V1(when there are no instrument errors) = 1.1 -1.0 = 0.1 Volt

Maximum error in measuring V2-V1 = Maximum measured value  - correct value =

0.205 - 0.1 = 0.105 volts

Hence maximum error = 0.105 volts 

 

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