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Answer

0.6×0.4+0.4×0.4

So, the probability of her studying computer science on Wednesday is 0.4, that's option C

Answer
Given answer is wrong
Answer

 

pre concept:

for example if aishwarya studies mathematics on tuesday for sure, (ie. if probability of studying mathematics on tuesday is 1), then we get the probabilty of studying computer science on wednesday is 1*0.4=0.4

Solution:

As aishwarya is studied computer science on monday, the probability that she reads maths on tuesday is 0.6.

then the probability of her studiying computer science on monday = (probability of studying mathematics on tuesday)*(prbability of reading computer science on wednesday) = 0.6*0.4=0.24

Answer
.4 since she studied computer science on Monday then every alternate day her probability of studying computer will remain same
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See the image, i solved and captured it
Answer
1) probability of studying maths on Tuesday and computer science on Wednesday= 0.6*0.4= 0.24 2) probability of studying computer science on both days= 0.4*0.4 =0.16 Now adding both, we get 0.4 So the correct option is "C"
Answer
(C) reqd probabilty = she studies math on tue and comp on wed OR comp on tue and comp on wed = 0.6×0.4 + 0.4×0.4 = 0.24 +0.16 = 0.4
Answer
Aishwarya studies computer science on Monday =>The probability that she studies Mathematics on Tuesday is 0.6 and the probability that she studies computer science on Tuesday is 0.4 => She studies Mathematics on Tuesday and Computer science on Wednesday =0.6×0.4 =0.24 ...(1) She studies computer science on Tuesday and Computer science on Wednesday =0.4×0.4 =0.16. ...(2) Adding 1 and 2, the required probability that she studies computer science on Wednesday =0.24+0.16=0.40 Ans. C

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