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Answer

3/6=4/8 this is a blanced wheet stone bridge, then we can remove 7ohm resistance.

total resistance= (4+3)*(8+6)/(7+14)= 14/3 = 4.67ohm

Answer
Since 3/6=4/8 so the above circuit is wheatstone bridge Therefore net resistance =(3+4)×(6+8)/(3+4)+(6+8) =7×14/21=14/3 ohm
Answer

For the above circuit, we get a balanced Wheatstone bridge, because 3Ώ/4Ώ=6Ώ/8Ώ. Hence the point R and S will be at the same potential. Hence no current will flow through the resistance 7Ώ. The network is therefore equivalent to two resistances (3+4)Ώ and (6+8)Ώ joined in parallel. Equivalent resistance R will be 1/R=1/7+1/14

∴ R= 14/3= 4.67Ώ

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