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Percentage Examples With Solutions

Published in: GRE
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This PPT is a very important chapter about Percentage Examples with Solutions.

Kiran R / Ahmedabad

15 years of teaching experience

Qualification: B.Sc (Tech) (UICT, MUMBAI - 1982)

Teaches: Bank PO, MBA Entrance, GMAT, GRE, SAT, CAT Exam

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  1. N/A
  2. ?. EXPRESS 0.02 % IN FRACTION 1/5000, 2/1000, 5/100, 1/100 0.02 0.02 100 2 10000 5000
  3. 2, EXPRESS 0.2 AS RATE 0/0 10 0/0, 20 0/0, 40 0/0, 2 10 2 -x 100 = 10
  4. FIND OF 30 3. 70 x 21 100 10, 20, 30, 40
  5. 4. WHAT 0/0 OF 96 IS 8? 6044, 8033, 9.6, 7.5 OF 8 = x = 8.33 0/0 96
  6. 90.48, 110.5, 133.33, 125.5 120 90 - x 100 = 133033 0/0 OF
  7. 6. WHAT 0/0 IS 5 GMS OF 1 KG? 0.7 0/0, 0.5 0/0, 0.2 0/0, 0.65 0/0 5 100 = x 100 = 0.5 0/0 OF 1000
  8. 7. IN A CLASS, NUMBER OF BOYS IS MORE THAN NUMBER OF GIRLS BY OF TOTAL STRENGTH. FIND RATIO OF BOYS TO GIRLS. 29/12, 14/11, 35/13, 55/12
  9. LET NO. OF BOYS & NO. OF GIRLS TOTAL STRENGHT = AS PER SUM CONDITION, EQUATION WILL BE OF (X + y) 12 100 25Y= 3Y = 28Y 3 25 x 28 22 11
  10. 8. THE RADIUS OF THE CIRCLE IS INCREASED BY FIND 0/0 INCREASE IN IT'S AREA.
  11. RADIUS AREA 100 101 0/0 IN AREA = 100 - x 100 ( 10201 - ) 201 - x 100 = (10000 ) 100 2.01 0/0
  12. 9. A MAN'S SALARY WAS DECREASED BY 50 AGAIN THE DECREASED SALARY WAS INCREASED BY 50 0/0. FIND 0/0 LOSS. 15 0/0, 20 0/0, 25 0/0, 30 0/0
  13. LET ORIGINAL SALARY = Rs. 100 NOW, SALARY BY = Rs. 50 SO, NEW SALARY = Rs. 50 NOW, SALARY Ted BY i.e. of 25 SO HIS REVISED SALARY = Rs 75 LOSS IN SALARY = Rs. 100-75 = 25 0/0 LOSS IN SALARY = 25
  14. 10. A MAN SPENDS OF HIS INCOME. HIS INCOME IS INCREASED BY 200/0 & HE INCREASED HIS EXPENSE BY 10 FIND 0/0 INCREASE IN SAVINGS. 10 0/0, 30 0/0, 50 0/0, 60 0/0
  15. INCOME EXPENSE SAVINGS 0/0 SAVINGS = X 100 = x 100 = x 100 = 50 0/0 100 75 25 37.5 - 25 25 120 82.5 37.5 12.5 25
  16. 11. THE PRICE OF AN ITEM IS INCREASED BY 200/0 & THEN DECREASED BY 20 0/0. FIND FINAL PRICE COMPARED -ro ORIGINAL PRICE. 4% MORE, LESS, MORE, 4% LESS
  17. LET ORIGINAL PRICE = Rs 100 Ted BY 20 0/0 = 120 wed BY 20 0/0 = 120 - OF 120 120- 24 96 DIFFERENCE IN THE PRICE = 100-96 4 FINAL PRICE IS LESS
  18. 12. ONE LITR OF WATER IS EVAPORATED FROM 6 LITR OF A SOLUTION CONTAINING 4% OF SUGAR. FIND 0/0 OF SUGAR IN NEW SOLUTION. 5 0/0, 8 0/0, 3.5 0/0, 4.8 0/0
  19. SUGAR CONTENT IN 6 LITR OF SOLUTION 4% OF 6 100 24 - KG 100 NOW 1 LITR WATER IS EVAPORATED SUGAR CONTENT REMAINS THE SAME LIT SOLN 100 - SUGAR 6/25 100 24
  20. 13. IF OF THE STUDENTS IN A SCHOOL ARE BOYS & NUMBER OF GIRLS IS 420. FIND NUMBER OF BOYS. 1000, 1260, 1500, 900
  21. LET TOATAL NO. OF BOYS = X SINCE ARE BOYS, GIRLS ARE 25 GIRLS ARE 420 - of x = 420 25 -x (x) = 420 x = 1680 100 NO. OF BOYS = OF 1680 75 -x 1680= 1260 100
  22. 14. IF OF W EQUALS OF T, FIND WHAT 0/0 OF T IS W? 12 0/0, 60 0/0, 33.33 0/0, 120 0/0
  23. 600/0 0f W = 200/0 0f ? 60 100 20 100 WHAT % ?? ? lS W ?/? 100 = 100 = ? 100 = - 100
  24. 15. IF 18 IS NUMBER. FIND NUMBER. OF OF A CERTAIN 200, 400, 150, 450
  25. LET ??? NUMBER ????? 1596 ?? 300/0 ?? ? = 18 15 ?? ? ? ? = 18 100 100 18 ? 10000 = 400 15 ? ??
  26. 16. DUE -ro PRICE HIKE OF 25 0/0, 5 KG LESS SUGAR IS AVAILABLE FOR 100. FIND ORIGINAL PRICE OF SUGAR.
  27. - Rs. M / KG Let original price - NEW PRICE = M + OF M 25 100 5M - KG 4 RS 100 - RS 100 SUGAR 1 KG SUGAR 1 KG 100/ M KG 80/M KG 100 DIFFERENCE IS 5 KG = M 20 80 M
  28. 17. THE FRACTION x/Y IS ALTERED BY DECREASING X BY & INCREASING Y BY 25 0/0. THE NEW FRACTION IS WHAT 0/0 LESS THAN ORIGINAL FRACTION. 20 0/0, 15 0/0, 30 0/0, 40 0/0
  29. N/A