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Friction

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Published in: Physics
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Friction

Vibaava A / Chennai

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  1. FRICTION
  2. Friction Any force that resists motion ' It involves objects that are in contact with each other. This is the force that keeps an object from sliding down and incline plane.
  3. ' Some scientists believe that friction is caused by uneven surfaces of the touching objects — when rubbed together resistance is offered. ' Experiments have shown that tiny particles are actually torn from one surface and imbedded in the other. ' If two surfaces were carefully polished, there is a limit to the amount by which friction may be reduced. If made too smooth, the friction between them actually increases.
  4. Examples of Friction Tires on the road Walking/Running Nails into wood Sled on hill
  5. Principles of Friction Friction acts parallel to the surface that are in contact. The direction that friction acts is OPPOSITE the direction of the motion (or intended motion). friction(k) normal applied weight
  6. There are two types of friction: > Static Friction — the frictional force present just before motion begins. Starting Friction is when Static Friction is at is maximum. Kinetic Friction — the frictional force present with motion *Note: Static Friction is usually higher than Kinetic Friction
  7. Friction depends on the nature of the material in contact and the smoothness of their surfaces. Static Friction is usually higher than Kinetic Friction because it is harder to get something started than it is to keep it going. Friction is practically independent of the area of contact
  8. The Coefficient of Friction Frictional Force, both static and kinetic, is directly proportional to the force pressing the two surfaces together. The more weight, the more friction. friction nornul The missing link to the above equation is the Coefficient of Friction, or g: = "Fnornnl friction static friction (static) Ukinetic nonml friction (kinetic) norrml
  9. PROBLEMS A 75 kg crate is to be pushed up an incline plane 5 m long that makes an angle of 200 with the horizontal. If the coefficient of static friction between the crate and the inclined plane is 0.20, how much force must be given to get it started up the incline? If the coefficient of kinetic friction is 0.15, how much applied force is needed to keep it going at a constant speed up the incline.
  10. Given: m=75 kg; m; 9=200; uS=O.20; uro.15 Fw=mg
  11. Fa=Fs + F =389.51N Fsf = = 0) Fp = mg(sin 0) -138.13 N = 251.38 N *note : this is the threshhol d. AT LEAST this much force is needed = 103.60 N = 251.38 N Fp = mg(sin 0) = 354.98 N *note : This is for CONSTANT speed.
  12. Take into account the last problem. After you have the crate moving up the incline at a constant speed, you want to give it an acceleration of 1.7 m/s2. What is the new force needed to accomplish this task?
  13. Fsf - = 0) — mg(sin O) F = 251,38 N kf P = 482,48 N
  14. A 300 kg sled is pulled at constant speed over a level, horizontal, snow covered surface. The rope that is used to pull the sled makes a 300 angle with the horizontal. If the coefficient of friction is 0.10, find the force required.
  15. Given: m=300 kg; 9=300; 9 Plk=o.10 Fy (sin 9) F x (COS 9) Fax-Ff=max *note: axis 0 because we are at a constant speed Fay+Fn-Fw=may *note: ayis 0 because the sled never moves up and down
  16. FRICTION
  17. Friction Any force that resists motion ' It involves objects that are in contact with each other. This is the force that keeps an object from sliding down and incline plane.
  18. FRICTION
  19. ' Some scientists believe that friction is caused by uneven surfaces of the touching objects — when rubbed together resistance is offered. ' Experiments have shown that tiny particles are actually torn from one surface and imbedded in the other. ' If two surfaces were carefully polished, there is a limit to the amount by which friction may be reduced. If made too smooth, the friction between them actually increases.
  20. Examples of Friction Tires on the road Walking/Running ' Nails into wood ' Sled on hill
  21. Friction Any force that resists motion ' It involves objects that are in contact with each other. This is the force that keeps an object from sliding down and incline plane.
  22. ' Some scientists believe that friction is caused by uneven surfaces of the touching objects — when rubbed together resistance is offered. ' Experiments have shown that tiny particles are actually torn from one surface and imbedded in the other. ' If two surfaces were carefully polished, there is a limit to the amount by which friction may be reduced. If made too smooth, the friction between them actually increases.
  23. Examples of Friction Tires on the road Walking/Running ' Nails into wood ' Sled on hill
  24. Principles of Friction Friction acts parallel to the surface that are in contact. The direction that friction acts is OPPOSITE the direction of the motion (or intended motion). friction(k) normal applied weight
  25. There are two types of friction: > Static Friction — the frictional force present just before motion begins. Starting Friction is when Static Friction is at is maximum. Kinetic Friction — the frictional force present with motion *Note: Static Friction is usually higher than Kinetic Friction
  26. Principles of Friction Friction acts parallel to the surface that are in contact. The direction that friction acts is OPPOSITE the direction of the motion (or intended motion). friction(k) normal applied weight
  27. Friction depends on the nature of the material in contact and the smoothness of their surfaces. Static Friction is usually higher than Kinetic Friction because it is harder to get something started than it is to keep it going. Friction is practically independent of the area of contact
  28. There are two types of friction: > Static Friction — the frictional force present just before motion begins. Starting Friction is when Static Friction is at is maximum. Kinetic Friction — the frictional force present with motion *Note: Static Friction is usually higher than Kinetic Friction
  29. The Coefficient of Friction Frictional Force, both static and kinetic, is directly proportional to the force pressing the two surfaces together. The more weight, the more friction. friction nornul The missing link to the above equation is the Coefficient of Friction, or g: nonml static friction (static) "kinetic nornul friction (kinetic) nonml
  30. Friction depends on the nature of the material in contact and the smoothness of their surfaces. Static Friction is usually higher than Kinetic Friction because it is harder to get something started than it is to keep it going. Friction is practically independent of the area of contact
  31. PROBLEMS A 75 kg crate is to be pushed up an incline plane 5 m long that makes an angle of 200 with the horizontal. If the coefficient of static friction between the crate and the inclined plane is 0.20, how much force must be given to get it started up the incline? If the coefficient of kinetic friction is 0.15, how much applied force is needed to keep it going at a constant speed up the incline.
  32. Given: m=75 kg; m; 6=200 Fp=mg(sin9) ; us=o.20; 14=0.15 Fw=mg 9
  33. The Coefficient of Friction Frictional Force, both static and kinetic, is directly proportional to the force pressing the two surfaces together. The more weight, the more friction. friction nornul The missing link to the above equation is the Coefficient of Friction, or g: nonml static friction (static) "kinetic nornul friction (kinetic) nonml
  34. Fa=Fs + F -389.51 N Fsf = = 0) -138.13 N = 251.38 N * note : this is the threshhol d. AT LEAST this much force is needed Fa = Fu+F = gsmg(cosO) Fp = mg(sin 0) = 354.98 N *note : This is for CONSTANT speed. = 103.60 N = 251.38 N
  35. PROBLEMS A 75 kg crate is to be pushed up an incline plane 5 m long that makes an angle of 200 with the horizontal. If the coefficient of static friction between the crate and the inclined plane is 0.20, how much force must be given to get it started up the incline? If the coefficient of kinetic friction is 0.15, how much applied force is needed to keep it going at a constant speed up the incline.
  36. Take into account the last problem. After you have the crate moving up the incline at a constant speed, you want to give it an acceleration of 1.7 m/s2. What is the new force needed to accomplish this task?
  37. Given: m=75 kg; m; 6=200 Fp=mg(sin9) ; us=o.20; 14=0.15 Fw=mg 9
  38. —F kf P Fsf = AF n = gsmg(cos O) = mg(sin O) F = 251,38 N
  39. Fa=Fs + F -389.51 N Fsf = = 0) -138.13 N = 251.38 N * note : this is the threshhol d. AT LEAST this much force is needed Fa = Fu+F = gsmg(cosO) Fp = mg(sin 0) = 354.98 N *note : This is for CONSTANT speed. = 103.60 N = 251.38 N
  40. A 300 kg sled is pulled at constant speed over a level, horizontal, snow covered surface. The rope that is used to pull the sled makes a 300 angle with the horizontal. If the coefficient of friction is 0.10, find the force required.
  41. Take into account the last problem. After you have the crate moving up the incline at a constant speed, you want to give it an acceleration of 1.7 m/s2. What is the new force needed to accomplish this task?
  42. FRICTION
  43. Given: m=300 kg; 9=300; 9 Fy (sin 9) +1 Fx (COS 9) *note: ax is O because we are at a constant speed Fay+Fn-Fw=may *note: ay is 0 because the sled never moves up and down
  44. Friction Any force that resists motion ' It involves objects that are in contact with each other. This is the force that keeps an object from sliding down and incline plane.
  45. —F kf P Fsf = AF n = gsmg(cos O) = mg(sin O) F = 251,38 N
  46. A 300 kg sled is pulled at constant speed over a level, horizontal, snow covered surface. The rope that is used to pull the sled makes a 300 angle with the horizontal. If the coefficient of friction is 0.10, find the force required.
  47. ' Some scientists believe that friction is caused by uneven surfaces of the touching objects — when rubbed together resistance is offered. ' Experiments have shown that tiny particles are actually torn from one surface and imbedded in the other. ' If two surfaces were carefully polished, there is a limit to the amount by which friction may be reduced. If made too smooth, the friction between them actually increases.
  48. Given: m=300 kg; 9=300; 9 Fy (sin 9) +1 Fx (COS 9) *note: ax is O because we are at a constant speed Fay+Fn-Fw=may *note: ay is 0 because the sled never moves up and down
  49. Examples of Friction Tires on the road Walking/Running ' Nails into wood ' Sled on hill
  50. Principles of Friction Friction acts parallel to the surface that are in contact. The direction that friction acts is OPPOSITE the direction of the motion (or intended motion). friction(k) normal applied weight
  51. There are two types of friction: > Static Friction — the frictional force present just before motion begins. Starting Friction is when Static Friction is at is maximum. Kinetic Friction — the frictional force present with motion *Note: Static Friction is usually higher than Kinetic Friction
  52. Friction depends on the nature of the material in contact and the smoothness of their surfaces. Static Friction is usually higher than Kinetic Friction because it is harder to get something started than it is to keep it going. Friction is practically independent of the area of contact
  53. The Coefficient of Friction Frictional Force, both static and kinetic, is directly proportional to the force pressing the two surfaces together. The more weight, the more friction. friction nornul The missing link to the above equation is the Coefficient of Friction, or g: nonml static friction (static) "kinetic nornul friction (kinetic) nonml
  54. PROBLEMS A 75 kg crate is to be pushed up an incline plane 5 m long that makes an angle of 200 with the horizontal. If the coefficient of static friction between the crate and the inclined plane is 0.20, how much force must be given to get it started up the incline? If the coefficient of kinetic friction is 0.15, how much applied force is needed to keep it going at a constant speed up the incline.
  55. Given: m=75 kg; m; 6=200 Fp=mg(sin9) ; us=o.20; 14=0.15 Fw=mg 9
  56. Fa=Fs + F -389.51 N Fsf = = 0) -138.13 N = 251.38 N * note : this is the threshhol d. AT LEAST this much force is needed Fa = Fu+F = gsmg(cosO) Fp = mg(sin 0) = 354.98 N *note : This is for CONSTANT speed. = 103.60 N = 251.38 N
  57. Take into account the last problem. After you have the crate moving up the incline at a constant speed, you want to give it an acceleration of 1.7 m/s2. What is the new force needed to accomplish this task?
  58. —F kf P Fsf = AF n = gsmg(cos O) = mg(sin O) F = 251,38 N
  59. A 300 kg sled is pulled at constant speed over a level, horizontal, snow covered surface. The rope that is used to pull the sled makes a 300 angle with the horizontal. If the coefficient of friction is 0.10, find the force required.
  60. Given: m=300 kg; 9=300; 9 Fy (sin 9) +1 Fx (COS 9) *note: ax is O because we are at a constant speed Fay+Fn-Fw=may *note: ay is 0 because the sled never moves up and down

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