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Time And Work

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Published in: GMAT | Management Subjects | Mathematics
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It is helpful for all competitive exams and government job exams.

Mayank / Delhi

9 years of teaching experience

Qualification: MBA/PGDM (Jamia Millia Islamia , Delhi - 2013)

Teaches: Economics, Geography, Science, Vedic Maths, Business Mathematics, DSSB, Police Department Exam, SSC CGL Exams, SSC Exams, Sub-Inspector Exam, BBA Entrance, MBA Entrance

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  1. Black holes of Aptitude-Time and Work Time and Work Type 1 Exp I Rizwan can do a piece of work in 6 days and Payam can do the same work in 8 days,working together ,in how many days they will complete the same work: Solution: Step I Take the L.C.M(6,8) of number of days taken by R and P alone to complete the work Imagine there are 24 bricks(Total work) in total , R can transfer all bricks in 6 days from one place to other, So he will have to pick 4 bricks a day and P will have to pick 3 bricks a day. 4 (24/6) 3(24/8) Step Il if P and R work together they will pick 7 bricks/day. Step Ill They can pick all 24 bricks in 24 — days Total Briks No of bricks picked /day 7 Type 11 Exp 2 Gulfshan and Maryam working together can do a piece of work in 8 days. If Gulfshan alone can do it in 24 days, in How many days Maryam alone can complete the same work? Solution: G+M-8 G—24 L.C.M (8, 24) 3(24/8) I (24/24) M alone can pick =2(3-1) bricks/day. So Maryam alone can do the same work in = 12 = 24 — days Total Briks No of bricks picked /day 2 OMayan Gupt &Shahnawaz Alam- [email protected]
  2. Black holes of Aptitude-Time and Work Type 111 Exp 3 If Afshan and Sahir can do a work in 18 days and 24 days respectively. They worked together for 8 days and then Afshan left. The remaining work was finished by Sahir in How many days? Solution: s-24 L.C.M (18, 4(72/18) 3(72/24) Step I A+S can pick 7(4+3) bricks/day. Step Il They worked for 8 days so, they will pick 56(8*7(4+3)) bricks in 8 days. step 111 Left over bricks 16(72-56) Step IV B will pick remaining 16 bricks in 16/3 days. Type IV Exp 4:Sajid can do a piece of work in 18 days and Haider in 12 days. They began the work together, But Haider left the work 3 days before its completion. In How many days in all was the work completed? Solution: s-18 H-12 L.C.M (18, 2(36/18) 3(36/12) Let say work was finished in N days ,So S worked for N days and H worked for X-3 days ,together they have to pick 36 bricks. OMayan Gupt &Shahnawaz Alam- [email protected]
  3. Black holes of Aptitude-Time and Work Total Bricks=no of days S worked>
  4. -15 L.C.M (15, Ah-25 Black holes of Aptitude-Time and Work 5(75/15) 3(75/25) M alone can pick =2(5-3) bricks/day. So Maryam alone can do the same work in 75 — days Total Briks No of bricks picked /day 2 Vll Exp7:If Manal can do a piece of work in 12 days and Najam can do it in 15 days. How many days it will take to complete the same work, If they work alternatively starting from Manal: Solution: M 12 14 60(L.C.M (12, 15)) 5(60/12) 4(60/15) Since they are working on alternate days, so they will pick 9(5+4) bricks in 2 days. Days 2 bricks 9 Now we will multiply bricks with a NUMBER which will make bricks near to total bricks (60), but not greater than 60, and we will multiply days with the same number. Days bricks 9x6(54) Now we are left with 6 bricks, since M has started work, now again its M's turn after 12 days work. Days 12 13 bricks 54 +5 59 OMayan Gupt &Shahnawaz Alam- [email protected]
  5. Black holes of Aptitude-Time and Work Now its N's turn and we are left with I brick, which can be picked by N in 1/4 days. no of bricks need to be picked no of bricks can be picked in a day 13+1/4 59+1=60 bricks So work will be complete in 13- days. TypeV111 Exp 8: Manal and Najam can do a piece of work in 12 days, Najam and Ayesha can do it in 15 days, Manal and Ayesha can do it in 20 days. how long it will take to complete the work, If they work together and alone? Solution: M+N 12 N+A 15 M+A 20 60 [L.C.M (12, 15, 20)] 60/12) 0/15) 3(60/20) Since there is double counting of every one so we will multiply total bricks by 2. —l Odays M+N+A 5+4+3 If we want to calculate it for M alone, we need to add bricks of those equations where M is present and subtracted those where M is absent 2 x 60 = 30 days Same for N and A N alone 2 x 60 = 20days A alone 2 x 60 = 60days OMayan Gupt &Shahnawaz Alam- [email protected]
  6. Black holes of Aptitude-Time and Work Type IX A=X+t1 B=X+t2 A+B-X=Vt1 x t2 Exp9: If Manal takes 16 hrs more to complete the work than Manal and Asra take together to do the same work and Asra takes 9 hrs more to do the same work than they together take. How many days it will take to finish the work if they work together? Solution: According to formula x=Vt1 x t2 x=V16 x 9 =12 days Type X Exp 10:1f A Men or B women or C children can do a piece of work in N days, How Many days it will take to complete the same work by D men and E women and F children: 1 1 3M or 4 W can do a piece of work in 43 days then 7 M and 5 W will do it in how many days? Solution: 1 Ans 1 Ans 1 N 14 BC 1 43 =12 days 37 1 12 OMayan Gupt &Shahnawaz Alam- [email protected]
  7. Type Xl Black holes of Aptitude-Time and Work M3xD3xH3 Exp I I :If40 men can finish a work in 60 days working 6 hrs a day, how long it will take to finish the double work by 60 men working 8 hrs a day? Solution: 40 x 60 x 6 1 =60 days Ml x DI x HI 60 x Dix 8 2 Exp12:A certain number of person can complete a piece of work in 55 days. If there were 6 person more, the work could have been finished in I I days less. How many person were originally there? Ml x DI x HI M x 55 (M + 6) x 44(55 - 11) 1 M=24 days Type Xll 1 Exp13:4 men and 6 women can complete the work in 8 days, While 3 men and 7 women can complete the work in 10 days, In how many days will 10 women and 5 men will complete the same work? (ii) 10 (i)=(ii) 32 M+48 W=30M+70W IM=I Take OMayan Gupt &Shahnawaz Alam- [email protected]
  8. Black holes of Aptitude-Time and Work We know that Ml x DI x HI (4M+6W) (4x11+6x1) D=80/13 days OMayan Gupt &Shahnawaz Alam- [email protected]

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