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Math Topic - Simplification

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Published in: Mathematics
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PBI I / Jalandhar

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  1. 1. PBI Simplification = (325000 - 300000) PBI INSTITUTE A classroom has equal number of boys and girls. Eight girls left to play kho-kho, leaving twice as many boys as girls in the classroom. What was the total number of girls and boys present initially? A. c. Solution 16 32 B. D. 24 48 Let the number of boys = x. Then, number of girls = x. Now, x- 8) = x. x= 16. Total number of students = 2x = 2 x16 = 32. 2. N number of persons decided to raise Rs. 3 lakhs by equal contribution from each. Had they contributed Rs. 50 each extra, the contribution would have been Rs. 3.25 lakhs. How many persons are there? A. c. Solution 400 550 B. D. 500 600 N X 50 3. = 25000 = 25000 / 50 = 500. In a classroom, if 6 students per bench are assigned to accommodate all students, one more bench will be required. However, if 7 students are accommodate per bench, there would be a space left for 5 students.What is the number of students in the class ? A. C. 30 42 B. D. 45 72
  2. Solution Let the number of benches in the class be x. Then, + 1) = -5 x = 11. Hence, number of students in the class PBI How may pieces of 85cm length can be cut from a rod 42.5 metres long? PBI INSTITUTE = 6 x 12 = 72. 4. 5.8 + 0.6 + 139.25= A. c. Solution Given exp. 157.30 158.40 B. D. 157.80 160.30 = 14.5 + 4.05 + 139.25 157.80. 5. On a sports day, if 30 children were made to stand in a column, then 16 columns could be formed. If 24 children were to stand in a column, then how many columns could be formed? A. c. Solution 20 29 B. 22 Total number of children Number of columns of 24 children each 6. A. 30 c. 60 = (30 x 16) 480. = (480 / 24) B. 40 D. None of these
  3. PBI Solution Number of pieces PBI INSTITUTE = (42.5 / 85 ) = 4250 / 85 = 50 7. In a regular week, there are 5 working days and for each day, the working hours are 8. A man gets Rs. 2.40 per hour for regular work and Rs. 3.20 per hours for overtime. If he earns Rs. 432 in 4 weeks, then how many hours does he work for ? A. 160 c. 180 Solution Suppose the man works overtime for x hours. Now, working hours in 4 weeks Therefore, 160 x 2.40 + x x 3.20 = 432 B. 175 D. 195 - 160. 3.20x = 432 - 384 = 48 x = 15. Hence, total hours of work = 8. What fraction of an hour is a second? A. 1/24 c. 1/ 120 Solution Required fraction (160 + 15) = 175. B. 1/60 D. 1/ 3600 = 1 sec/ 1 hr — 1 sec / (1 x 60 x 60) sec = 1/ 3600. 9. A man earns on the first day and spends Rs. 15 on the next day. He again earns Rs. 20 on the third day and spends Rs. 15 on the fourth day. If he continues to save like this, how soon will he have Rs. 60 in hand? A. on 17th day C. on 30th day Solution Money earned in 2 days Money earned in 16 days On 17th day, money in hand B. on 27th day D. on 40 th day = Rs.(20 - 15) 15. = Rs.(5/2 x 16) 40. - Rs.(40 + 20 ) = Rs. 60. 10. In a garden there are 10 rows and 12 columns of mango trees. The distance between the two trees is 2 metres adn a distance of one metre is left from all sides of the boundary of the garden. The length of the garden is A. 20m C. 24m Solution Each row contains 12 plants. B. 22 m D. 26m Leaving 2 cornerplants, 10 plants in between have ( 10 x 2) metres and 1 metre on each side is left.
  4. PBI PBI INSTITUTE Length 11. = (20 + 2) m = 22 m. A boy was asked to multiply a number by 25. He instead multiplied the next number by 52 and got the answers 324 more than the correct answer. The number to be multiplied was A. 10 c. 15 Solution Let the number be x. Then, 52 x- 25 x = 324 < = > 27 X = 324 12. 12. On simplification 3034 - (1002 +20.04) is equal to B. 12 D. 25 B. 2984 D. 3029 A. 2543 c. 2993 Solution Given exp. 13. 3640 +14 A. 0.70 c. 4500 = 3034 - ( 1002 / 2004 = 3034 - 50 =2984. x 16 + 340 = ? B. D. = 260 x 16 + 340 = 4160 + 340 3525 9600 Solution Given exp. 14. Solution Along a yard 225 metres long, 26 trees are palnted at equal distances, one tree being at each end of the yard. What is the distance between two consecutive trees? A. 9 metres C. 15 metres B. 12 metres D. 18 metres 26 trees have 25 gaps between them. Required distance = (225 / 25)m

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