Statistics Tutors for Class 9 - 10 in Vadodara

Statistics is study of numbers /data provided by arranging them and deriving meaningful conclusions using statistical tools and techniques. It's a field of study where we decipher information using available data.

You will get marks on your explanation. It depends on the examiner. Well if you have explained the kink you will get 2 or above.

Solving the equations we get the means of x and y. Here it is x=130 and y=90 Rewriting the first equation as y=(1/2)x+25 and second equation as x=(3/2)y-5, and multiplying the coefficients on the right side, we get (1/2)(3/2)=3/4 which is less than 1. (otherwise we must consider rewriting the equations the other way) This value is square of the correlation coefficient. Therefore taking square root, we get the correlation coefficient as r =root(3)/2=0.866.

According to Croxton and Cowden “Statistics is defined as “the science which deals with the collection, analysis, and interpretation of numerical data”According to Croxton and Cowden “Statistics is defined as “the science which deals with the collection, analysis, and interpretation of numerical data” This defination is from the book "Fundamentals of Mathematical Statistics" by S.C. Gupta and V.K. Kapoor

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Let probability of getting tail p(T)=1/2 let it is success i.e p =1/2 probability of getting head p(H)=1/2 i.e not getting tail q=1/2 By bernoulli trial p(X =x) = nCx q^(n-x)p^x where n =4 p(X=x) = 4Cx(1/2)^(4-x)×(1/2)^x p(X=x) =4Cx(1/2)^4 probability of getting atmost 1 tail p(X

Team A has 60 students.

4 are eliminated by their own team hence chance of getting eliminated by A team is 4/60 and 2 are eliminated by team B. Hence chance of eliminating A's team by B team is 2/60

Hence toatal chance of eliminating A's team memeber is 4/60*2/60= 1/15*1/30= 1/145

Similarly, for B team the total probability of elimination is 3/20*1/20= 3/400

Variation due to assignable cause in product occurs due to difference in Total quality management policies of a firm. Variation in strict maintainence and implementation of quality ensuring techniques like quality check, quality circles, kiazen etc leads to variation in assignable cause in a product. Since the assignable cause refers to a detectable error at the firms level, and this occurs due to non complaince of check at the very first level of oocurence rather than identifying when the product is made. Hence the variation in assignable cause is due to variation or lack in quality checks

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