Maths Teachers in Jharoda Majraa, Delhi

Answer:

Let the sum  given on 10% rate of  compound interest for 3 years is Rs 100.

Interest for Rs 100 for one year at the above interest rate is Rs 10

Therefore total amount accrued  at the end of first year=Rs100+Rs10= Rs 110

Now this becomes the principal for the second year. Interest for  one year for Rs 110= Rs 11

Therefore total amount accrued at the end of second year=Rs110+Rs11=  Rs 121

Now this becomes the principal for the third year. . Interest for one year for Rs 121=Rs12.10

Therefore total amount accrued at the end of third year = Rs 121+Rs 12.10=  Rs 133.10

For  accrued amount of Rs 133.10, the principal sum =    Rs 100

For accrued amount of Rs 6655/- ,the principal sum=      (6655x 100)/ 133.10)= Rs 5000 

The required sum= Rs 5000

1- right angle 2- angle 3- draw a straight line and put protractor's lower half circle at one end point of line....now observe where exactly is 130° showing on protractor Nd mark it ...now join end point of that line and marked 130° point on paper. 4- 360/5 = 72° 5- draw a circle n divide in angle of 60° each 6 parts.

Solution

To draw an angle of 130 degree kindly follow the these instruction

Step1 : make an angle of 120 degree

Step2 : make an angle of 135 degree Step3 : put the compass on 135 degree and make an arc. Step4 : now put the compass on 120 degree and make an arc. Step5 : draw a line by joining intersected part of your arc and join it with base line

it is angle PQR not LPQR. we can draw angle 130 degree with protector which is quite easy but we also draw it with the help of compass.

1)  we draw 60 and 120 with compass

2) mark two point from 120 degree than cut the first point from 180 degree.than take first cuted point and cut another point which is taken priviously.

3) than take centre of both the points with the help of compass.and match that new point to the centre.

4)the point which is intersect at semi circle is consider and the point if 120 degree is taken. than locate the centre of both point. than we get 130 degree after joining it with centre.

file is not able to upload. so, please contact me for answer with photo.

Let A ={1,2,3}

Subsets are {}(empty set) ; {1}; {2}; {3}; {1,2}, {1,3}, {2,3} and {1,2,3}  giving us a total of 8 subsets

But, empty set and A(set itself) are not considered as proper subsets.

Hence, number of proper subsets are 8-2 = 6

OR

No. of proper subsets are given by 2^n - 2, where n is no. of elements in the set

Hence, in this case 2^3 - 2 = 6  

Answer: Pl see the attached file

Refer to the anwer below:

Given: tanA + cotA = 2

To find: tan2A- cot2A

Sol:     (tanA - cotA)2 =(tanA + cotA)2 - 4tanAcotA

                                  = 4 - 4

          (tanA - cotA)2 = 0

            tanA - cotA   = 0

=>    tan2A - cot2A  = (tanA + cotA) (tanA - cotA)

                                = 2 X 0

                                =0   (Ans.)

Terminating numbers are those numbers which come to an end after few repetitions after decimal point.

Terminating numbers Example: 0.5, 2.456, 123.456, etc. ...1/2, 9/3, 7/5 etc... 

Non terminating numbers are those which keep on continuing after decimal point (i.e. they go on forever).

Non terminating numbers Example: 1/3, 10/9 etc..