Maths Teachers in Chhawla, Delhi

Let the sum be P , A=P( 1+ r/100)^n , A= Amount , r= rate of interst , n=Number of year , P= Principal.

Here A = Rs. 6655 , R= 10% , n= 3 years.

P( 1+ 10/100)^3 = 6655  Or , P(1+1/10) ^3 =6655 Or, P( 11/10)^3 =6655 Or , 1331P/1000 =6655

Or , 1331P= 6655000 Or , P= 6655000/1331 Or P = 5000

The Sum is Rs : 5000

1- right angle 2- angle 3- draw a straight line and put protractor's lower half circle at one end point of line....now observe where exactly is 130° showing on protractor Nd mark it ...now join end point of that line and marked 130° point on paper. 4- 360/5 = 72° 5- draw a circle n divide in angle of 60° each 6 parts.

Solution

To draw an angle of 130 degree kindly follow the these instruction

Step1 : make an angle of 120 degree

Step2 : make an angle of 135 degree Step3 : put the compass on 135 degree and make an arc. Step4 : now put the compass on 120 degree and make an arc. Step5 : draw a line by joining intersected part of your arc and join it with base line

it is angle PQR not LPQR. we can draw angle 130 degree with protector which is quite easy but we also draw it with the help of compass.

1)  we draw 60 and 120 with compass

2) mark two point from 120 degree than cut the first point from 180 degree.than take first cuted point and cut another point which is taken priviously.

3) than take centre of both the points with the help of compass.and match that new point to the centre.

4)the point which is intersect at semi circle is consider and the point if 120 degree is taken. than locate the centre of both point. than we get 130 degree after joining it with centre.

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Let A ={1,2,3}

Subsets are {}(empty set) ; {1}; {2}; {3}; {1,2}, {1,3}, {2,3} and {1,2,3}  giving us a total of 8 subsets

But, empty set and A(set itself) are not considered as proper subsets.

Hence, number of proper subsets are 8-2 = 6

OR

No. of proper subsets are given by 2^n - 2, where n is no. of elements in the set

Hence, in this case 2^3 - 2 = 6  

Answer: Pl see the attached file

Refer to the anwer below:

Given: tanA + cotA = 2

To find: tan2A- cot2A

Sol:     (tanA - cotA)2 =(tanA + cotA)2 - 4tanAcotA

                                  = 4 - 4

          (tanA - cotA)2 = 0

            tanA - cotA   = 0

=>    tan2A - cot2A  = (tanA + cotA) (tanA - cotA)

                                = 2 X 0

                                =0   (Ans.)

Terminating numbers are those numbers which come to an end after few repetitions after decimal point.

Terminating numbers Example: 0.5, 2.456, 123.456, etc. ...1/2, 9/3, 7/5 etc... 

Non terminating numbers are those which keep on continuing after decimal point (i.e. they go on forever).

Non terminating numbers Example: 1/3, 10/9 etc..