1. The ideal transformer is a model of transformer with a coupling coefficient equal to unity(1). 2. The operation of ideal transformer is the same in the time domain as in the frequency domain.

Answer: Please refer to the attached files

Please refer the attached file.

Answer

Let V,W,R be the voltage , power rating and  resistance respectively of each lamp.

Then power rating of each lamp W= V^2/ R  =200 watts

Now when the 2 identical lamps are connected in series the voltage gets equally divided between the 2 lamps

and so voltage across each lamp=   V/2.

Therefore power consumed  by each lamp=  {(V/2)^2}/R= V^2/(4R)

Therefore power consumed by both  lamps= 2*(V^2)/(4R)= V^2/(2R) =  (V^2 /R)/2=W/2= 200/2=100 watts

Answer:

1. Separately Excited Generator:

Let E be the induced EMF, Ia be the armature current, Ra  be  the armature resistance and Ig be  the load current of the separately excited generator. As the excitation current of the  generator does not pass through the motor circuit, the current through the armature will be same as load current Ig and so voltage  drop will be  Ig * Ra.  Hence terminal voltage V of the generator   is given by the equation:

          V= E-   Ig * Ra

2. Shunt excited Generator:  Let Ish  be the shunt field current. This current and load current Ig pass through armature      circuit. The armature current will therefore be Ish+ Ig.. So the voltage drop is (Ish+ Ig) * Ra.. Hence terminal voltage of the generator   is given by the equation:   

V= E- (Ish+ Ig) * Ra

3. Series Excited Generator: Let Rse be the resistance of  the series winding .The same load current Ig  flows through both the armature and the series field winding. Therefore the total voltage drop will be Ig * (Ra+.Rse)..Hence terminal voltage of the generator  is given by the equation:  

V=  E- Ig * (Ra+. Rse)

4.Compound Excited Generator:  The current in the armature  circuit/ the series field winding will be sum of   the load current Ig and shunt field current Ish. Therefore   the voltage drop will be   (Ish+ Ig) * (Ra+ Rse).  Hence terminal voltage of the generator  is given by the equation:

V=  E- ( Ish+ Ig) * (Ra+ Rse)

the answer is given below,

Yes. (Learnpick Admin, I hope you are literate and technically sound enoough to understand this question. My answer is precise. Student is checking if he can use Raspberry Pi or not. Please do not reject my answer. Please reject question. Thanks)

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Magnetic flux density is defined as the number of magnetic lines of flux passing through a point on a surface. It is denoted by the symbol B. The SI unit of magnetic flux density is Tesla

An Alternating Current Voltage is one in which the value of either the voltage or the current varies about a particular mean value and reverses direction periodically.